Answer:
B. 8
Step-by-step explanation:
simply just plug the possible answers into the equation for x. plugging in 7 comes out to 39, or one short, so 8 is the answer because the question asks for the fewest ads to run to get the 40 customer goal
Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Answer:
47.75 + x Less-than-or-equal-to 50
= 47.75 + x ≤ 50
Step-by-step explanation:
Solving the above Question:
Not going over the 50 pound case mean, less than or equal to 50 pounds
Let the extra pound of weight be represented as x
Hence, the inequality equation that can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit =
47.75 + x ≤ 50