What is the length of the midsegment of a trapezoid with bases of length 15 and 25 ?
1 answer:
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I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
First we look for the hypotenuse of both triangles.
Left triangle:
Sine (68.1) = (1.75) / (h)
h = (1.75) / Sine (68.1)
h = 1.886108667
h = 1.9m
Right triangle:
Sine (49.4) = (1.75) / (h)
h = (1.75) / Sine (49.4)
h = 2.304841475
h = 2.3m
Finally adding the perimeter:
P = 5 + 1.9 + 2.75 + 2.3
P = 11.95 m
Answer:
she will need to build 11.95 m of fence
SEE ATTACHED IMAGE.
First we look for the hypotenuse of both triangles.
Left triangle:
Sine (68.1) = (1.75) / (h)
h = (1.75) / Sine (68.1)
h = 1.886108667
h = 1.9m
Right triangle:
Sine (49.4) = (1.75) / (h)
h = (1.75) / Sine (49.4)
h = 2.304841475
h = 2.3m
Finally adding the perimeter:
P = 5 + 1.9 + 2.75 + 2.3
P = 11.95 m
Answer:
she will need to build 11.95 m of fence