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Harlamova29_29 [7]
4 years ago
13

What is the x-value of the solution to this system of equations? x = 2y − 4 7x + 5y = -66

Mathematics
1 answer:
saveliy_v [14]4 years ago
3 0
X=2y - 4 7 xI hope it helps sorry if it doesn’t
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4 0
3 years ago
Calculus help! Using the mean value theorem!
marta [7]
f is differentiable across its domain, so the MVT says there is some value of c in the open interval (a,b) such that

f'(c)=\dfrac{f(b)-f(a)}{b-a}

You have

f(x)=Ax^2+Bx+C\implies f'(x)=2Ax+B

so the equation above becomes

2Ac+B=\dfrac{(Ab^2+Bb+C)-(Aa^2+Ba+C)}{b-a}

Solve for c.

2Ac+B=\dfrac{A(b^2-a^2)+B(b-a)}{b-a}
2Ac+B=A(b+a)+B
2Ac=A(b+a)
c=\dfrac{b+a}2

so c is indeed the average of the endpoints, i.e. the midpoint.
8 0
3 years ago
7b ÷ 12 = 4.2  what does b =
Luda [366]
7b/12=4.2
7b=50.4
b=7.2

hope this helps
3 0
3 years ago
Read 2 more answers
Q10 A student wants to raise £100 for charity.
ElenaW [278]

Answer:

He must charge minimum £0.84 for one hot dog.

Step-by-step explanation:

Ingredients cost for hot dogs at the supermarket,

Price of dog sausages tin of 8 = 50p ≈ £0.5

Price of dog bun packs of 6 = 90p ≈ £0.90

Number of tins required for 150 hot dogs = \frac{150}{8} = 6.25

So student will purchase 7 tins.

Cost of 7 tins = 7 × 0.5

                      = £3.5

Number of dog buns packets required = \frac{150}{6} = 25

Cost of 25 packs = 25 × 0.9

                            = £22.5

Total cost of the material used for 150 buns = 22.5 + 3.5

                                                                         = £26.0

Let the selling price of each hot dog = £x

Then selling price of 150 hot dogs = £150x

Students wants the profit = £100

So, Selling price - Cost price = profit

150x - 26 = 100

150x = 126

x = \frac{126}{150}

x = £0.84

Therefore, he must charge minimum £0.84 for one hot dog.

8 0
3 years ago
Please help just say A,B,C, Or D if you don’t feel like giving examples. Thank you
Mashcka [7]

D. is the correct anser

7 0
3 years ago
Read 2 more answers
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