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alexandr402 [8]
3 years ago
11

What is the value of y? 18+2y+4+10+2x+10

Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

1) 18+2y+4+10+2x+10

2) 42+2y+2x

3) 42+2x=-2y

4) -1(42-2x=2y)

5) (42-2x=2y)/2

y=21-x

Step-by-step explanation:

1) Original equation

2) Combine like terms

3) Since the problem is asking to find the value of Y, Isolate it

4) Multiply by a negative to make Y positive

5) Since what we have left isn't in simplest form, divide by 2

What is left is y=21-x or y=-x+21

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How does the volume of an oblique cylinder change if the radius is reduced to 2/9 of its original size and the height is quadrup
vesna_86 [32]
Volume of a cylinder = π r² h

Let us assume the following values:
radius = 9
height = 10

Volume = 3.14 * 9² * 10
            = 3.14 * 81 *10
Volume = 2,543.40

Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40

Volume = π r² h
             = 3.14 * 2² * 40
             = 3.14 * 4 * 40
Volume = 502.40

Original volume = 2543.40   V.S.  Volume after change = 502.40

The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times. 
4 0
3 years ago
I WILL GIVE BRAINLIEST
shusha [124]

Answer:

x = -3

Step-by-step explanation:

y\geq -\frac{2}{3} x-3\\
y\leq 3x+8

-\frac{2}{3} x-3=3x+8

Add 2/3 x to both sides:  -3=\frac{11}{3}x+8

Subtract 8 from both sides: -11=\frac{11}{3}x

Multiply both sides by 3:  -33=11x

Divide both sides by 11:  x=-3

Therefore, point of intersection between both lines is at point (-3, -1)

5 0
2 years ago
An arhitect wants to draw a rectangle with a diagonal of 20 inches. The length of the rectangle is to be 8 inches more than twic
kiruha [24]

The diagonal of a rectangle = sqrt(w^2 + l^2)

w = width

l = length

In this problem,

The diagonal = 20 in

w = x

l = 2x + 8

Let's plug our numbers into the formula above.

20in = sqrt((x)^2 + (2x + 8)^2)

Let's simplify the inside of the sqrt

20 in = sqrt(5x^2 + 32x + 64)

Now, let's square both sides.

400 = 5x^2 + 32x + 64

Subtract 400 from both sides.

0 = 5x^2 + 32x - 336

Factor

0 = (5x - 28)(x + 12)

Set both terms equal to zero and solve.

x + 12 = 0

Subtract 12 from both sides.

x = -12

5x - 28 = 0

Add 28 to both sides.

5x = 28

Divide both sides by 5

x = 28/5

The width cant be a negative number so now we know that the only real solution is 28/5

Let's plug 28/5 into our length equation.

Length = 2(28/5) + 8 = 56/5 + 8 = 96/5

In conclusion,

Length = 96/5 inches

Width = 28/5

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hichkok12 [17]
What’s the question?
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Answer:

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