Answer:
18.75%
Step-by-step explanation:
Hello,
3 students are both female and senior
the total number of students is 7+10+8+5=30
so the probability to select one female senior is 3/30=1/10=0.10
probability to select one female is 16/30=16/30
probability that the student is a senior given that it's female is
=P(female and senior)/P(female)
=1/10*30/16=3/16
hope this helps
Are theese questions or your answers
if there answers they seem all right
To do this we take the outlier off the parenthesis (the 4) and multiply it by the two numbers inside the parenthesis...
4*7 + 4*8
28+32
Answer:
the number (x) is 120.
Explanation:
<em>100% + 60% = 160% = 1.6 </em>
<em />
<em>(just multiply it by 1.6 because it is equal to 60%)</em>
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
