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RSB [31]
3 years ago
11

Write an equation of the line passing through the points (4, 15) and (-2, -21).

Mathematics
1 answer:
Alla [95]3 years ago
8 0

Step-by-step explanation:

(y2-y1)/(x2-x1)=(y-y1)/(x-x1)

(-21-15)/(-2-4)=( y-15)/(x-4)

6(x-4)=y-15

6x-y-9=0

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3 years ago
What curve passes through the point ​(1 ​,2​) and has an arc length on the interval​ [2,6] given by Integral from 2 to 6 StartRo
Georgia [21]

Answer:

Step-by-step explanation:

Given

Length of curve

L=\int_{2}^{6}\sqrt{1+64x^{-6}}dx

Length of curve is given by

L=\int_{a}^{b}\sqrt{1+\left ( \frac{\mathrm{d} y}{\mathrm{d} x}\right )^2}dx over interval a to b

comparing two we get

\frac{\mathrm{d} y}{\mathrm{d} x}=8x^{-3}

dy=8x^{-3}dx

integrating

\int dy=\int 8x^{-3}dx

y=-4x^{-2}+C

Curve Passes through (1,2)

1=-4+C

C=5

curve is

y+\frac{4}{x^2}=5

3 0
3 years ago
Please help answer this :)
jolli1 [7]

Answer:

ok

Step-by-step explanation:

yeah

8 0
3 years ago
Width = (b - a)/n = (8 - 0)/4 = 2
Nookie1986 [14]
Yes, I'm getting C also!

Since it's asking for the left-endpoint Riemann Sum, you will only be using the top left point as the height for each of your four boxes, making -1, -2.5, -1.5, and -0.5 your heights. The bases are all the same length of 2. You don't include f(8) because you're not using right-endpoints, and that would also add another 5th box that isn't included in the 0 to 8 range.
7 0
4 years ago
Read 2 more answers
Geometry help pleaseeeee
Nonamiya [84]
C. Obtuse hope this helps (lmk if you get it right)
6 0
3 years ago
Read 2 more answers
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