What is an equation of the line that is parallel to y=5x−7 and passes through (1, 11) ?

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

y = 5x+6 is equation of line that is parallel to y=5x−7 and passes through (1, 11).

Step-by-step explanation:

We have given a equation.

y = 5x−7 and (x₁,y₁) = (1,11)

We have to find the equation which is parallel to given equation and passing through the given point.

y-y₁ = m(x-x₁) is equation of line where m is slope.

Given equation have slope equal to 5.

Parallel lines have equal slopes.

Hence, m = 5

Putting the value sin equation of line, we have

y-11 = 5(x-1)

y-11 = 5x-5

y = 5x-5+11

y = 5x+6 is equation of line that is parallel to y=5x−7 and passes through (1, 11).

garik1379 [7]3 years ago

4 0

Answer:

y = 5x + 6

Step-by-step explanation:

parallel lines have equal slopes, implying that the slope of the new line will be 5 as well.

The equation of this new line in slope intercept form is;

y=5x+c

We determine c by using the point where this new line passes through, that is the point (1, 11)

11=5(1)+c

c=6

The equation is thus;

y = 5x + 6

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