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3 years ago

What is an equation of the line that is parallel to y=5x−7 and passes through (1, 11) ?

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

y = 5x+6 is equation of line that is parallel to y=5x−7 and passes through (1, 11).

Step-by-step explanation:

We have given a equation.

y = 5x−7 and (x₁,y₁) = (1,11)

We have to find the equation which is parallel to given equation and passing through the given point.

y-y₁ = m(x-x₁) is equation of line where m is slope.

Given equation have slope equal to 5.

Parallel lines have equal slopes.

Hence, m = 5

Putting the value sin equation of line, we have

y-11 = 5(x-1)

y-11 = 5x-5

y = 5x-5+11

y = 5x+6 is equation of line that is parallel to y=5x−7 and passes through (1, 11).

garik1379 [7]3 years ago

4 0

Answer:

y = 5x + 6

Step-by-step explanation:

parallel lines have equal slopes, implying that the slope of the new line will be 5 as well.

The equation of this new line in slope intercept form is;

y=5x+c

We determine c by using the point where this new line passes through, that is the point (1, 11)

11=5(1)+c

c=6

The equation is thus;

y = 5x + 6

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Answer:

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Step-by-step explanation:

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3 years ago

What is the diameter of a circle with the equation (x – 4)2 + (y + 6)2 = 64?

Ronch [10]

Answer:

The diameter of a circle with the equation is 16.

Step-by-step explanation:

Given the equation

$\left(x\:-\:4\right)^2\:+\:\left(y\:+\:6\right)^2=\:64$

We know that the circle equation with radius 'r', centered at (a, b)

$\left(x-a\right)^2+\left(y-b\right)^2=r^2$

$\mathrm{Rewrite}\:\left(x-4\right)^2+\left(y+6\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}$

$\left(x-4\right)^2+\left(y-\left(-6\right)\right)^2=8^2$

Here,

radius = r = 8

center = (4, -6)

Hence, the radius of the circle is: r = 8

we know that

diameter = 2r

= 2(8)

= 16

Therefore, the diameter of a circle with the equation is 16.

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3 years ago

Read 2 more answers

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frosja888 [35]

6p
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4 years ago

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Mkey [24]

Answer:

See below

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Increasing

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