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melamori03 [73]
3 years ago
12

Given parallelogram efgh what is the length of side ef

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

Answer:

23

Step-by-step explanation:

first, you solve for side EH, and set it equal to 33, which is the side that corresponds to EH. After you have the value for x, plug it into the equation for HG, then solve.

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Find the area of the compound shapes below !Please help
jenyasd209 [6]

Answer:

86cm

Step-by-step explanation:

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X^2-2x−4=0 please leave ans in surd form and simplify​
Jobisdone [24]

Step-by-step explanation:

using the quadratic formula......

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3 years ago
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Becky needs to transfer liquid to a vase using a cylindrical container with a radius of 5 centimeters and a height of 10 centime
Svetradugi [14.3K]

Answer:

Becky needs approximately 3 containers to fil the vase up to 75%.

Step-by-step explanation:

In order to solve this problem we first need to calculate the volume of the container as shown below:

volume = pi*r²*h = pi*5²*10 = 250*pi = 785 cm³

Since becky wants to fill 75% of the vase capacity, she needs to fill:

goal = 2800*75/100 = 2100 cm³

Therefore Becky needs a total of

containers =  goal/volume

containers = 2100/785 = 2.67

Becky needs approximately 3 containers to fil the vase up to 75%.

6 0
3 years ago
Who knows how you do you this??
Monica [59]
Hi!
Okay, so this actually isn't too bad! (For number 5) Just add the negative x over to get 2x. Then subtract 2 over to get -10. Then divide by 2 (-5) and you're done! For the rest, do the same thing. Get the x's on one side, get the regular numbers on the other, and divide! Hope that helped!
4 0
3 years ago
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Please help me with it is for homework<br><br> I really need help please help me
Solnce55 [7]

Answer:

See explanation

Step-by-step explanation:

Given two expressions:

2(s+0.5)+2(s+1.5)

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4

a. When s=0,

then

2(s+0.5)+2(s+1.5)=2(0+0.5)+2(0+1.5)=1+3=4

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 0+\dfrac{1}{4}\cdot 0\right)+4=4

b. When s=12,

then

2(s+0.5)+2(s+1.5)=2(12+0.5)+2(12+1.5)=2\cdot 12.5+2\cdot 13.5=25+27=52

and

4\left(\dfrac{1}{2}s+\dfrac{1}{4}s\right)+4=4\left(\dfrac{1}{2}\cdot 12+\dfrac{1}{4}\cdot 12\right)+4=4(6+3)+4=4\cdot 9+4=36+6=40

c. Since the value of both expressions at s = 12 are different, the expressions are not equivalent.

6 0
3 years ago
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