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2 years ago

What is the distance between points (2, 4) and (3, 1) to the nearest tenth?

Mathematics

1 answer:

Karolina [17]2 years ago

4 0

Answer:

3.2

Step-by-step explanation:

You might be interested in

The ____ is the horizontal distance between two points.

timama [110]

The length of line segment is the horizontal distance between two points

Suppose

a line has endpoints

(x-1,y1)
(x2,Y2)

The length of the line is

√(x_1-x_2)²+(y_1-y_2)²

6 0

1 year ago

Please show an explanation

Ber [7]

Answer:

You should go to algebraic calculator. its amazing

Step-by-step explanation:

brainliest?

4 0

2 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

I dont understand how to answer this question, help please?

kakasveta [241]

It is A. ....... i wish you had a whole chart

8 0

2 years ago

If you need 8 oz of chocolate chips to make 1.6 lb of cookie dough how many ounces of chocolate chips will you need to make 7 lb

iren [92.7K]

Answer:

3.5 Oz of chocolate

Step-by-step explanation:

1.6 lb of cookie dough is made from chocolate of 8 Oz

1 lb will be made by 8/ 1.6 = 0.5 Oz of chocolate

Therefore

7lb of cookie dough will be made from 7 * 0.5= 3.5 Oz of chocolate/

6 0

3 years ago