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RideAnS [48]
3 years ago
14

What is the distance between points (2, 4) and (3, 1) to the nearest tenth?

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

3.2

Step-by-step explanation:

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answer What happens to the probability of landing on blue as more and more sections are added to the spinner?
sveta [45]

Answer: the probability of landing on blue as more and more colors are added is low because as you add more colors there is less and less of the blue

Step-by-step explanation: i am honestly just guessing dont come at me!!!

8 0
2 years ago
Madeline sold 200 tickets for a charter flight to Dallas. Some paid $200 for their tickets and some paid
4vir4ik [10]

Answer:

Let x = number of regular tickets sold.

Let y represent the number of student tickets sold.

12x+8y≤100012x+8y≤1000

x+y≥200x+y≥200

12x+8y≤20012x+8y≤200

x+y≤200x+y≤200

12x+8y≥1000

hope this helps

Step-by-step explanation:

8 0
2 years ago
According to the ratio of the age, if Rs. 216 is divided to the girls of age 8, 9 ad 10 yearsHow much money will each get ​
SSSSS [86.1K]

9514 1404 393

Answer:

  • 8 years: Rs. 64
  • 9 years: Rs. 72
  • 10 years: Rs. 80

Step-by-step explanation:

The sum of ages is 8+9+10 = 27, so each year of age is rewarded by ...

  216/27 = 8 . . . Rs

Then age 8 gets 8(Rs. 8) = Rs. 64

  age 9 gets 9(Rs. 8) = Rs. 72

  age 10 gets 10(Rs. 8) = Rs. 80

3 0
3 years ago
Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I
dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06

Find the probability of getting a mean temperature of 98.2 degrees F or lower.

This is the pvalue of Z when X = 98.2. So

Z = \frac{X - \mu}{s}

Z = \frac{98.2 - 98.6}{0.06}

Z = -6.67

Z = -6.67 has a pvalue of 0.

So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.

8 0
3 years ago
I really need the answers as soon as possible. So I hope you answer this
SpyIntel [72]
Ignore bottom one please brainiest. edit: add cubed after the second bracket

8 0
3 years ago
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