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3 years ago

Between 1910 and 1930, what was the approximate increase in us homes with electricity

2 answers:

4 0

nearly 68 percent of American homes were electrified. But, if you don't count farms, about 85 percent of Americans had electricity by the end of the 1920s.

And there's the rub. Rural communities, including farms, were far slower in adopting electricity than the rest of the country. Of the roughly 6.3 million American farms in 1922, only about 3% had electricity. It wasn't until 1935 that the U.S. government addressed this huge rural vs urban electric divide with the formation of the Rural Electrification Administration.

True [87]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

What is the image of the point (4, -8) after a rotation of 270° counterclockwise

saw5 [17]

Answer:

( -8, -4)

Step-by-step explanation:

Think of the graph as 4 different sections,

top left is 1

top right is 2

bottom right is 3

bottom left is 4

The red dot is (4, -8) and the blue dot is ( -8, -4 )

If you move from the right side of the grid to the left you would switch (x ,y ) to (y , x).

depending on what part of the graph it is in, it will be negative or positive.

hope this helps!

8 0

3 years ago

Root of 9216 in prime factorisation

DaniilM [7]

Answer:

The square root of 9216 is 96

Step-by-step explanation:

Given the number 9216 we have to find the square root of 9216 by <u>Prime factorization method</u>

Prime factors of 9216 are

2*2*2*2*2*2*2*2*2*2*3*3= 9216

Now, make pairs of same factors and choose one factor out of every pair and then take the product.

Hence, the square root of 9216 is 96

5 0

4 years ago

Help ASAP

SIZIF [17.4K]

Answer:

Answer

4.0/5

17 7/8÷3 2/5

143/8÷17/5

Step-by-step explanation:

multiply by reciprocal

143/8×5/17= 715/136= 5.26 which is closer to

B. 6

7 0

3 years ago

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o

BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :( $b^4,b^2,b^4$ )

$b^4$ = b × b × b × b

$b^2$ = b × b

$b^4$ =b × b × b × b

GCF of variables :( $b^4,b^2,b^4$ ) is $b^2$

3) GCF of $c^3$ and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.