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faust18 [17]
3 years ago
7

Between 1910 and 1930, what was the approximate increase in us homes with electricity

Mathematics
2 answers:
navik [9.2K]3 years ago
4 0

nearly 68 percent of American homes were electrified. But, if you don't count farms, about 85 percent of Americans had electricity by the end of the 1920s.

And there's the rub. Rural communities, including farms, were far slower in adopting electricity than the rest of the country. Of the roughly 6.3 million American farms in 1922, only about 3% had electricity. It wasn't until 1935 that the U.S. government addressed this huge rural vs urban electric divide with the formation of the Rural Electrification Administration.

True [87]3 years ago
3 0

Answer:

55

Step-by-step explanation:

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A population of 40 wolves triples every year. Which graph below represents the population growth?
Afina-wow [57]
Option 4 because the number of wolves increases
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3 years ago
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The path of a satellite orbiting the earth causes it to pass directly over two tracking stations A and 8, which are 60 mi apart.
vesna_86 [32]

Answer:

(a)  2 miles

 (b)  2 miles

Step-by-step explanation:

Let the distance of the satellite from Station A = |AC|

Let the height of the Satellite from the ground = |DC|

(a) Using size rule on triangle ABC, we can find the value of AC with the following relationship:

|AC|/ Sin 84.2 = 10/ Sin 8.8

|AC| = 10 x (Sin 84.2/Sin 8.8)

         =   10 x 0.1529

        =1.529 miles

        = 2 miles (to the nearest mile)

(b) To calculate the |DC|, we apply the relationship of right-angle triangle ADC:

Sin 87 =   |DC|/ 1.529

|DC|   = 1.529 Sin 87

           = 1.526 miles

           = 2 miles (to the nearest mile)

6 0
3 years ago
i need help with this question... the word "GC" in the question stands for graphic calculator so u could just ignore that part o
Katyanochek1 [597]
X coodinate is one
y = 1+ 3/(2x+1)
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5 0
3 years ago
Given A(0,-4), B(0,-9), and C(-2,-5). Find the length of BC.
Ivan

Answer:

4.5

Step-by-step explanation:

B(0,-9)

C(-2,-5)

=> BC = \sqrt{(-2-0)^{2} -(-5+9)^{2} }  = 4.4721

5 0
3 years ago
Compare the perimeters of the two regular figures. Which statement is true?
adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be=\frac{(n-2){\timeS}180^{\circ}}{6}

=\frac{(6-2){\timeS}180^{\circ}}{6}

=\frac{(4){\timeS}180^{\circ}}{6}

=120^{\circ}

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

\frac{MP}{MQ}=cos60^{\circ}

MP=\frac{1}{2}

Thus, the perimeter of the hexagon is:

P=12{\times}MP

P=12{\times}\frac{1}{2}

P=6 units

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be=\frac{(n-2){\timeS}180^{\circ}}{8}

=\frac{(8-2){\timeS}180^{\circ}}{8}

=\frac{(6){\timeS}180^{\circ}}{8}

=135^{\circ}

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore {\angle}PAC=cos\frac{135}{2}.

From ΔAPC, we have

AC=cos\frac{135}{2}

Now, Perimeter of octagon is:

P=16{\times}cos\frac{135}{2}

P=16{\times}0.382

P=6.122 units

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

4 0
3 years ago
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