I'm trying to do this problem, but I have no idea how to even start it:

In order to qualify for a role in a play, an actor must be taller than 64 inches but shorter than 68 inches. The inequality 64 &

Oksanka [162]

It can be written 68 > x > 64.

5 0

3 years ago

Read 2 more answers

The maximum load of a horizontal beam that is supported at both ends varies jointly as the width and the height and inversely as

dezoksy [38]

Answer:

$360kg$

Explanation:

Here, we want to get the maximum load supported

From the first part of the question, we have it that:

The maximum load g, varies jointly with the width w and the height h, and inversely as the length l between the supports

Mathematically, we have that as:

$g\text{ = k }\times\frac{wh}{l}$

where k is the proportionality constant

Now, let us get the value of k

We substitute the first set of values as follows:

$\begin{gathered} 360\text{ = }\frac{k\times0.1\times0.06}{6} \\ \\ k\text{ = 360,000 }\frac{kg}{m} \end{gathered}$

Now, using this value of k, we want to get the value of g

Mathematically, we have that as:

$g\text{ = }\frac{360,000\times0.2\times0.08}{16}\text{ = 360 }kg$

8 0

1 year ago

5^2+x^2=10^2<br><br> What Is X and how do you find the angles for it?

Anvisha [2.4K]

If you work out the constants it says:

25+x²=100

Which simplifies to x=√75 or x=-√75

4 0

3 years ago

b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum

Mariana [72]

Answer:

${52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4$

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in ${52 \choose 7}$ ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in ${7 \choose 2}$ ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in ${45 \choose 7}$ . Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in ${7 \choose 2}$ ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in ${38 \choose 7}$ . And again, we have to choose which ones are the hidden ones, which can be chosen in ${7 \choose 2}$ ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in ${31 \choose 7}$ ways. And choosing which ones are the hidden ones for this player can be done in ${7 \choose 2}$ ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

${52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4$

7 0

3 years ago

Three people invest in a treasure dive, each investing the amount listed below. The dive results in 40 gold coins. Apportion tho

garri49 [273]

Answer:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

Step-by-step explanation:

We know that the dive results in 40 gold coins.

We know that:

Alice: $7,600 Ben: $5,900 Carlos: $1,400.

So they have $ 14900 in total.

Now we will divide that money by 40.

$x=\frac{14900}{40}\\\\x=372.5$

So 1 gold coin costs $ 372.5. Now we will calculate how much they can get for the money they have.

$A=\frac{7600}{372.5}=20.4\\\\B=\frac{5900}{372.5}=15.8\\\\C=\frac{1400}{372.5}=3.75\\$

We conclude that:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

6 0

3 years ago