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AleksAgata [21]
2 years ago
5

The function f is defined by f(x) = x^2 + 2

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
7 0
It's simple,


f(x)=x^2+2
is the formula that you start with

you are then given f(x). f(4x)


you then plug in 4x

4x=(4x)^2+2

you then solve for x

4x=16x+2
-16x. -16x


-12x=2
÷-12. ÷-12

x=0.16 is your answer
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2.933 expanded form decimals
Shkiper50 [21]
Just put a period between everything 2.9.3.3
8 0
3 years ago
Zack deposited $1,200 in a savings account that paid 7.75% simple
Eddi Din [679]
<span>The correct answer is: Option (C) $1393.21

Explanation:
At the beginning of the Second year, the total balance would be:

$1200 + ($1200 * 7.75 / 100) = $1293

At the beginning of the Third year, the total balance would be:
$1293 + ($1293 * 7.75 / 100) = $1393.21 (Option C)</span>
6 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
1) A radio signal travels from the earth and through space at a speed of 300,000 km/s. How far into space would the signal trave
riadik2000 [5.3K]

Answer:

1. 24,000,000, i believe you divide, 300,000/80.

2. 4.065 seconds, i also believe you divide 5000m/1230.

7 0
3 years ago
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Veseljchak [2.6K]
4(5w-3) -(w-1)
(9w-12)-(w-1)
8w-11
4 0
3 years ago
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