To solve for the midpoint of the segment we use the equation that is given as:
(x1 + x2 / 2) , (y1 + y2 / 2)
For the points given,
(x1 + x2 / 2) , (y1 + y2 / 2)
(3+ 2 / 2) , (-5 + 9 / 2)
(5/2 , 2) or (2.5 , 2)
Hope this answers the question. Have a nice day. Feel free to ask more questions.
<h2>
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Total surface area of cone is 176π
<h3>Explanation:</h3>
Surface area of curved surface of a cone is give by π⋅r.l , where r is the radius and l is the slant height of the cone.
Hence surface area of curved surface of a cone is π×8×14=112π .
As surface area of base is π×82=64π .
Hence total surface area is 112π+64π=176π
Answer:
This equation is equivalent to 
<em>Hope this helps and have a great day!</em>
<em />
Answer: 1.1818^37 kg
Step-by-step explanation:
Given that:
Orbit speed = 1300 km/s
Radius (r) = 18 light days
Mass of object the star is orbiting :
Using the relation :
M = rv² / G
Where ; r = Radius in m ; v = velocity in m/s
G = 6.67 * 10^-11 = gravitational constant
18 light days in meters = 4.662 * 10^14 m
v = 1300km/s to m/s
v = (1300 * 1000)m /s = 1300000 m/s = 1.3 * 10^6 m/s
Hence ;
M = (4.662 * 10^14 * (1.3 * 10^6)^2 / (2/3) * 10^-10
M = (4.662 * 10^14) * (1.69 * 10^12) / (2/3) *10^-10
M = (7.87878 * 10^26) / 6.67 * 10^-11
= 1.1818^37 kg
