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2 years ago

The measure of angle 3 is 42°. What is the measure of angle 1 in degrees?

Mathematics

1 answer:

netineya [11]2 years ago

7 0

Answer:

measure of angle 1

= 180° - 90° - 42°

= 48°

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The formula C=kmt is used to find the number of calories a person burns during exercise, where m is the person’s weight in pound

Ludmilka [50]

C = kmt
k = C/mt

Units of k are Calories per pound - minute.

4 0

2 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

2 years ago

Find the x <br> Please help me and show how you got it :)

Kaylis [27]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

The parallel lines divide the sides proportionally, so ratios of corresponding sides are the same.

(x +5)/15 = (5x +1)/35

Multiplying by 105, we have ...

7(x +5) = 3(5x +1)

7x +35 = 15x +3 . . . . . eliminate parentheses

32 = 8x . . . . . . . . . subtract 7x+3 from both sides

4 = x . . . . . . . . divide by 8

4 0

2 years ago

An ice cream shop offers 5 different types of ice cream, 6 different toppings and the option of having a small, medium or large.

prohojiy [21]

Answer:

90 possible outcomes.

Step-by-step explanation:

In order to find the total number of combinations possible you simply need to multiply the total number of each options with one another. For example, the number of options in each category are the following

types: 5

toppings: 6

size: 3 (small, medium, large)

Now we simply need to multiply all three of these numbers together to find the total number of possible outcomes.

5 * 6 * 3 = 90 possible outcomes.

5 0

2 years ago

Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o

umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)

1/2 ∫▒(2xdx/u) =1/2 ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2 ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C (required soultion)

3 0

2 years ago

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