1. The mean of all the numbers is 41.
5. Median : 52
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
28.5^2
Step-by-step explanation:
The formula is, b(base)+c(height)= b+c over 2. b+c/2.
B=19ft in this problem.
C=38ft
Knowing this, we can further simplify.
19+38/2
Now, we add 19 and 38.
(57)
57/2= 28.5
So, the anwser is 28.5^2
Answer:
15
Step-by-step explanation:
Use the Pythagorean Thereom:
= 
+
= 81+144
= 225
= 15
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