The answer would be the distances that are not too large and not too small
A.legnth and width of a ball room
this would work because the next measurement is 1 mils and ball rooms are not that big
B. width of an eyelash. that is rediculously small so this is wrong
C. distanc from chicaco to san fransisco
way too far, use miles
D. height of a door
corect, door is apout 8 feet aprox
answer is A and D
Answer:
xvideos
Step-by-step explanation:
Answer:
Hypotenuse = 14.1421 inches (rounded off to four decimal values)
Step-by-step explanation:
The legs of an isosceles triangle both measure 10 inches
Since the triangle is a right triangle,
We apply the Pythagorean Theorem to find the height of the hypotenuse
a² + b² = c²
a = 10 inches, b = 10 inches and (c) is the hypotenuse whose value we don't know.
So; 10² + 10² = c²
c² = 100 + 100
c² = 200
c =
= 14.1421356237 inches
The hypotenuse is 14.1421 inches (answer rounded off to four decimal values)
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line


once you get the slope and solve for "y", that'd be the equation of the line.