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miv72 [106K]
3 years ago
14

The absolute value of -202.8

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
The answer is 202.8
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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

  • Mass of copper in x pounds of that 15\% copper alloy: (0.15\, x)\; \rm lb.
  • Mass of copper in 700 pounds of that 30\% copper alloy: 700 \times 0.30 = 210\; \rm lb.

Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

4 0
3 years ago
Rewrite the expression by combining like terms. 4x2 - 2x2 + 2y + 6y2 - y + x2​
olasank [31]

Answer:

32 +6y^2+

Step-by-step explanation:

3 0
3 years ago
What type of decimal is 0.275
Mnenie [13.5K]
D. Complex Decimal.
5 0
3 years ago
Read 2 more answers
R/7.1 = 4.2<br><br>what is r =​
MissTica

Answer:

r =29.82

Step-by-step explanation:

r/7.1 = 4.2

Multiply each side by 7.1

r/7.1 *7.1 = 4.2*7.1

r =29.82

8 0
3 years ago
What are the coordinates of the midpoint?
xz_007 [3.2K]

Answer:

Midpoint (4|7)

Step-by-step explanation:

A(2,6) and B(6,8)

at first add the x values and divide it by two

(2+6)/2=4

second, add the y values and divide it by two

(6+8)/2=7

Midpoint (4|7)

-> and you can see it it is exactly in the middle of line segment

3 0
3 years ago
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