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kotegsom [21]
3 years ago
10

Which expression is a difference of squares with a factor of 2x + 5?

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0
I am pretty sure it is 4(2+25) because if you factor it out you will get the factores form you got before.
You might be interested in
What is the justification for each step in the solution of the equation?
otez555 [7]

23x-13=2(x+2)

First you would distribute the 2 into the parenthesis

It will look like this after: 23x-13=2x+4

Then you would subtract 2x on both sides because u have to get the x's on one side

It will look like this after:21x-13=4

Then you would add 13 to both sides

It will look like this after: 21x=17

Then you would divide 21 on both sides

Your final product is 21/17


7 0
3 years ago
2(a-7)=a+4<br> 15 6<br>PLS HELPPPPPPPPPPP​
muminat

Answer:

a = 18

Step-by-step explanation:

2(a-7)=a+4

Distribute 2 into left side: 2a -14 = a + 4

subtract a from both sides  2a-a-14 = a+4-a

Simplify: a  - 14 = 4

Add 14 to both sides: a - 14 + 14 = 4 +14

Simplify:   a = 18

If wanted, plug a into original to double check work:

plug in: 2 (18-7) = 18+4

do parenthesis first: 2 (11) = 18+4

do multiplication : 22 = 18+4

additions: 22 =22

a = 18 is correct.

8 0
3 years ago
Read 2 more answers
(3 x 105 ) x (2 x 103 )
anzhelika [568]

Answer:

64,890

Step-by-step explanation:

105×3 =315

103×2= 206

315×206= 64,890

6 0
3 years ago
Read 2 more answers
Calculate the area of this trapezium. ​
Alla [95]
It the talk empty side it will be 8 and the line will be 4 tell me if I am wrong
3 0
3 years ago
An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


4 0
3 years ago
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