For this case we have the following system of equations:
To solve, we clear "x" from the second equation:
We substitute "x" in the first equation:
We clear the value of the variable "y":
We look for the value of the variable "x":
Thus, the solution of the system is given by:
Answer:
Option D
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
Use the explantion to answer your question
Step-by-step explanation:
Amount he paid for first 20 shares
= $25 + (20 x $10.51)
= $25 + $210.20
= $235.20
Amount he paid for next 20 shares
= $25 + (20 x $8.93)
= $25 + $178.60
= $203.60
Thus, total amount paid
= $235.20 + $203.60
= $438.80
Answer: 24(2y−1)
Step-by-step explanation:
Factor 48y−24
48y−24
=24(2y−1)
Answer:
24(2y−1)
