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3 years ago

What is 0.689 in word form

Mathematics

1 answer:

kolezko [41]3 years ago

4 0

Six hundred eighty nine thousandths

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Solve

NISA [10]

Answer:

$r = 0.01$

Step-by-step explanation:

In order to find r we have to square both sides of the equation

$0.1 = \sqrt{r} \\ {0.1}^{2} = { \sqrt{r} }^{2}$

The *square root* sign cancels out the *squared* sign therefore:

${0.1}^{2} = r \\ 0.01 = r$

6 0

2 years ago

When Mischa filled her car's gas tank before beginning a trip, the car's odometer read 44,587 miles. When she stopped for gas ne

pantera1 [17]

Answer:

18.11 miles per gallon

Step-by-step explanation:

Get the miles traveled from the trip odometer, or subtract the original odometer reading from the new one.

Divide the miles traveled by the amount of gallons it took to refill the tank. The result will be your car’s average miles per gallon yield for that driving period.

44,895-44,587 = 308 miles

308/17 = 18.11

6 0

3 years ago

Suppose that many large samples are taken from a population and that the

rewona [7]

Answer:

$0.22 -1 *0.029 =0.191$

$0.22 +1 *0.029 =0.249$

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

$\bar X = 0.22$

And the standard error is given by:

$SE = 0.029$

We want to construct a 68% confidence interval so then the significance level would be :

$\alpha=1-0.68 = 0.32$ and $\alpha/2 =0.16$ . The confidence interval is given by:

$\bar X \pm z_{\alpha/2} SE$

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

$z_{\alpha/2}= 1$