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SOVA2 [1]
3 years ago
13

6. Pamel bought an electric drill at 85% of the regular price. She paid $276,25 for

Mathematics
1 answer:
Katen [24]3 years ago
3 0

Answer:

£325

Step-by-step explanation:

She paid £276.25 which is 85%

Divide 276.25 by 85 which is 3.25

3.25 is 1%

Multiply 3.25 by 100 to get the full Price

3.25 x 100 = £325

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line jk passes through points j(–4, –5) and k(–6, 3). if the equation of the line is written in slope-intercept form, y
likoan [24]

The y - intercept of the line is -21 .

Slope - inercept form of equation of line :

y = m x + c

where m is the slope and c is the y - intercept of the line .

Writing equation in slope - intercept form :

( - 5 - 3 ) / ( - 4 + 6 ) = ( y - 3 ) /( x + 6 )

( -8 ) / ( 2 ) = ( y - 3 ) /( x + 6 )

- 4 ( x + 6 )  = y - 3

- 4 x - 24 = y - 3

y = - 4 x - 21

Hence , the y - intercept of the line is -21 .

To learn more on equation of line follow link :

brainly.com/question/19417700

#SPJ4

4 0
1 year ago
In​ 2009, a diabetic express company charged ​$38.85 for a vial of type A insulin and ​$30.34 for a vial of type B insulin. If a
Hoochie [10]

Answer:

The number of vials of type A insulin sold were _<u>21</u>__ and the number of vials of type B insulin sold were __<u>29</u>__.

Step-by-step explanation:

Let a = number of type A vials.

Let b = number of type B vials.

38.85a + 30.34b = 1695.71

a + b = 50

            38.85a + 30.34b = 1695.71

(+)        -38.85a - 38.85b = -1942.50

---------------------------------------------------

                               -8.51b = -246.79

b = 29

a + b = 50

a + 29 = 50

a = 21

Answer: The number of vials of type A insulin sold were _<u>21</u>__ and the number of vials of type B insulin sold were __<u>29</u>__.

6 0
2 years ago
Which expression is the simplest form of (27x^-9)^1/3?
lana [24]
\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\\\(a^n)^m=a^{nm}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(27x^{-9})^\frac{1}{3}=27^\frac{1}{3}(x^{-9})^\frac{1}{3}=\sqrt[3]{27}\cdot x^{-9\cdot\frac{1}{3}}=3x^{-3}=\dfrac{3}{x^3}
8 0
3 years ago
If r(x) = 2 – x2 and w(x) = x – 2, what is the range of ? (w0r)(x)
TiliK225 [7]

Answer:

The range would be all real numbers

Step-by-step explanation:

In order to find (wor)(x), we need to start with the w(x) equation and then input the r(x) equation for every x in the w(x) equation.

w(x) = x - 2

(wor)(x) = (2 - x^2) - 2

(wor)(x) = -x^2

Given this equation, we know that x can be all real numbers

4 0
3 years ago
Read 2 more answers
Birds arrive at a birdfeeder according to a Poisson process at a rate of six per hour.
m_a_m_a [10]

Answer:

a) time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b) P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c) P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

P(T>t)= e^{-\lambda t}

a. What is the expected time you would have to wait to see ten birds arrive?

The original rate for the Poisson process is given by the problem "rate of six per hour" and on this case since we want the expected waiting time for 10 birds we have this:

time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b. What is the probability that the elapsed time between the second and third birds exceeds fifteen minutes?

Assuming that the time between the arrival of two birds consecutive follows th exponential distribution and we need that this time exceeds fifteen minutes. If we convert the 15 minutes to hours we have 15(1/60)=0.25 hours. And we want to find this probability:

P(T\geq 0.25h)

And we can use the result obtained from the definitions and we have this:

P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c. If you have already waited five minutes for the first bird to arrive, what is the probability that the bird will arrive within the next five minutes?

First we need to convert the 5 minutes to hours and we got 5(1/60)=0.0833h. And on this case we want a conditional probability. And for this case is good to remember the "Markovian property of the Exponential distribution", given by :

P(T \leq a +t |T>t)=P(T\leq a)

Since we have a waiting time for the first bird of 5 min = 0.0833h and we want that the next bird will arrive within 5 minutes=0.0833h, we can express on this way the probability of interest:

P(T\leq 0.0833+0.0833| T>0.0833)

P(T\leq 0.1667| T>0.0833)

And using the Markovian property we have this:

P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

3 0
3 years ago
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