Answer:
D.->6N
Explanation:
This is because <-2 N + -> 8 N
= <-2 N + -> 2 N + -> 6 N
= 0 N + -> 6 N
= -> 6 N
B+ Bb Ww male × B+ Bb Ww female Because beardedness and coat color independently assort, we can treat them independently. The difference between this cross and a dihybrid cross is that the bearded allele B b is dominant in males and recessive in females. So we deal with male and female progeny separately. For each sex, then, we should get a typical dihybrid ratio. In males, the dominant phenotype is bearded, so we should get ¾ bearded, ¼ beardless. In females the dominant phenotype is beardless, so we should get ¾ beardless and ¼ bearded. Each sex will have ¾ black and ¼ white coats.
Explanation:
Liquids and gases are similar in both shape and volume because they both have its shape determined by its surroundings.
Gases, liquids and solids are all made up of atoms, molecules, and/or ions
Answer:
both begin with glycolysis
Explanation:
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Answer:
When an E.coli cell is infected by multiple phages,they will take either lytic or lysogenic pathway.
Explanation:
When lambda phage bacteriophage infects an E.coli,it can either undergo lytic cell growth and lyse the host cell or enter lysogenic pathway.
The operator region of lac operon in E.coli contain single repressor binding site whereas the lambda operators
and
each contains 3 repressor binding sites (
and
) that are differently occupied under different conditions.
The differential affinity of lambda repressor for the three binding sites in these operators play an important role in the maintenance of lysogenic state of lambda prophage in E.coli.
The lytic development occurs in cells infected with lambda phage that carry
gene.
In contrast,lysogeny will occur in bacteria that infected with lambda phage that harbor a deletion of Cro gene.