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deff fn [24]
3 years ago
12

A rectangular parking lot has a perimeter of 820 ft. the area of the parking lot measures 42,000 ft^2. what is the width of the

parking lot
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0
Find the system :
2(x+y) = 820
xy = 42000
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Zeros of a polynomial function that cannot be shown on the coordinate plane are called ___ zeros.
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Answer:

w= -9 :)

Step-by-step explanation:

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Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro
puteri [66]

Answer:

(a) P(0 ≤ Z ≤ 2.87)=0.498

(b) P(0 ≤ Z ≤ 2)=0.477

(c) P(−2.20 ≤ Z ≤ 0)=0.486

(d) P(−2.20 ≤ Z ≤ 2.20)=0.972

(e) P(Z ≤ 1.01)=0.844

(f) P(−1.95 ≤ Z)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)=0.862

(h) P(1.01 ≤ Z ≤ 2.50)=0.150

(i) P(1.20 ≤ Z)=0.115

(j) P(|Z| ≤ 2.50)=0.988

Step-by-step explanation:

(a) P(0 ≤ Z ≤ 2.87)

In this case, this is equal to the difference between P(z<2.87) and P(z<0). The last term is substracting because is the area under the curve that is included in P(z<2.87) but does not correspond because the other condition is that z>0.

P(0 \leq z \leq 2.87)= P(z

(b) P(0 ≤ Z ≤ 2)

This is the same case as point a.

P(0 \leq z \leq 2)= P(z

(c) P(−2.20 ≤ Z ≤ 0)

This is the same case as point a.

P(-2.2 \leq z \leq 0)= P(z

(d) P(−2.20 ≤ Z ≤ 2.20)

This is the same case as point a.

P(-2.2 \leq z \leq 2.2)= P(z

(e) P(Z ≤ 1.01)

This can be calculated simply as the area under the curve for z from -infinity to z=1.01.

P(z\leq1.01)=0.844

(f) P(−1.95 ≤ Z)

This is best expressed as P(z≥-1.95), and is calculated as the area under the curve that goes from z=-1.95 to infininity.

It also can be calculated, thanks to the symmetry in z=0 of the standard normal distribution, as P(z≥-1.95)=P(z≤1.95).

P(z\geq -1.95)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)

This is the same case as point a.

P(-1.20 \leq z \leq 2.00)= P(z

(h) P(1.01 ≤ Z ≤ 2.50)

This is the same case as point a.

P(1.01 \leq z \leq 2.50)= P(z

(i) P(1.20 ≤ Z)

This is the same case as point f.

P(z\geq 1.20)=0.115

(j) P(|Z| ≤ 2.50)

In this case, the z is expressed in absolute value. If z is positive, it has to be under 2.5. If z is negative, it means it has to be over -2.5. So this probability is translated to P|Z| < 2.50)=P(-2.5<z<2.5) and then solved from there like in point a.

P(|z|

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Step-by-step explanation:

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Write the equation of the line perpendicular to 2x+3y=9 that passes through (-2,5). Write your answer in slope-intercept form. S
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ANSWER

y =  \frac{3}{2} x + 8



EXPLANATION

The line given to us has equation,

2x + 3y = 9

We need to write this equation in the slope intercept form to obtain,


3y =  - 2x + 9



\Rightarrow \: y =  -  \frac{2}{3}x + 3


The slope of this line is

m_1 =  -  \frac{2}{3}
Let the slope of the perpendicular line be

m_2

Then
m_1 \times m_2 =  - 1


-  \frac{2}{3} m_2=  - 1

This implies that,

m_2 =  - 1 \times  -  \frac{3}{2}


m_2 =  \frac{3}{2}



Let the equation of the perpendicular line be,

y = mx + b

We substitute the slope to get,


y =  \frac{3}{2} x + b

Since this line passes through
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This means that,

5=  \frac{3}{2} ( - 2)+ b


5 =  - 3 + b



5 + 3 = b


b = 8

Wherefore the slope-intercept form is

y =  \frac{3}{2} x + 8
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