A rectangular parking lot has a perimeter of 820 ft. the area of the parking lot measures 42,000 ft^2. what is the width of the
parking lot
1 answer:
Find the system :
2(x+y) = 820
xy = 42000
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Step-by-step explanation:
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[ Answer ]

[ Explanation ]
Parenthesis
Exponents
Multiply
Divide
Add
Subtract
Parenthesis:
3 * 2 = 12
12 - 12 = 0
12 - 0 = 12
10^2 * 12
10 ^ 2 = 144
144 * 12 = 1728
1728 + 15 = 1743
1743 + 6 = 10458