X^4 - 4x^3 - 9x^2 + 36x = 0
x(x^3 - 4x^2 - 9x + 36) = 0
x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0
the zeroes are -3, 0, 3, 4 Answer
Answer:
The value could replace q is 108 - n ⇒ the last answer
Step-by-step explanation:
* Lets study the values of quarters and nickles
- One quarter = 25 cents
- One nickle = 5 cents
- The number of coins is 108
- The coins are nickles or quarters only
- The coins worth $ 21
* Lets solve the problem
∵ The number of coins is 108 coins
- Let the quarter is q and the nickel is n
∴ q + n = 108 ⇒ (1)
∵ The coins worth $21
∵ $ 1 = 100 cents
∴ $21 = 21 × 100 = 2100 cents
∵ The quarter = 25 cents
∵ The nickels = 5 cents
∴ 25q + 5n = 2100 ⇒ (2)
- To find the value which replace q use equation (1)
∵ q + n = 108 ⇒ subtract n from both sides
∴ q = 108 - n
* The value could replace q is 108 - n
The last one is the right answer
