The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
In order to factor this, we will need to take something out to get it to factor. Lets take out a greatest common factor, in this case our greatest common factor will be 3.
We will then write it as:
-3(5t+2)
Answer:
999-Empty
Step-by-step explanation:
I ain't have anything then and I still don't have anything still, still, still
Bein' me, I rock PnB
These h03s actin' like gossip, TMZ
These drgs acting like
Moshpits squishing me
Oh my, oh me, how they kill me slowly
Lonely, I been gettin' no peace
OD, feel like OD
Low key I been looking for the signs
But all I can find is a sign of the times
Answer:
57709
Step-by-step explanation:
The answer is the last choice. (a, b), in this question, means the domain or range is from a to b, exclusive. When you use ∞, you would always use the exclusive.