I need help please

Mathematics

2 answers:

Viefleur [7K]3 years ago

5 0

Answer:

-1

Step-by-step explanation:

Wittaler [7]3 years ago

4 0

Answer:

-1

Step-by-step explanation:

rise over run

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What kind of function is being illustrated by f(x)=|2x³-3x|+5?

Dimas [21]

Answer:

Option D: Absolute value function

Step-by-step explanation:

The absolute value of a number is the distance of the number from 0 to the left or right on the number line.

We are given the function;

f(x) = |2x³ - 3x| + 5

This function contains an absolute value symbol which is |2x³ - 3x|.

This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.

5 0

3 years ago

Which is the correct simplified version of the expression -7(2x-3)

satela [25.4K]

A. -14x+21

because -7 times 2x is -14x and -7 times -3 is 21

7 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$