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3 years ago

If x=2 find y 5x-y=5

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

4 0

Answer:

y=5

solution,

X=2

now,

 $\\ 5x - y = 5 \\ or \: 5 \times x - y = 5 \\ or \: 5 \times 2 - y = 5 \\ or \: 10 - y = 5 \\ or \: - y = 5 - 10 \\or \: - y = - 5 \\ y = 5$ 

hope this helps..

Good luck on your assignment..

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What equation results from completing the square and then factoring? x^2-8x=39

erma4kov [3.2K]

We have that
x²-8x=39

Group terms that contain the same variable

(x²-8x)=39

Complete the square. Remember to balance the equation by adding the same constants to each side

(x²-8x+16)=39+16

Rewrite as perfect squares

(x-4)²=55-------> (x-4)²-55=0

(+/-)]x-4]=√55

(+)]x-4]=√55--------> x=4+√55

(-)]x-4]=√55-------> x=4-√55

the answer is

(x-4)²-55=0

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3 years ago

Read 2 more answers

75 points. Will give certified if work is shown and the answer is correct.

Svetach [21]

Volume of the first dwarf planet (r₁ = 832 mi):

$V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3$

Volume of the second dwarf planet (r₂ = 829 mi):

$V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3$

So difference between the volumes is:

$V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}$

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

$V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}$

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3 years ago

Derek runs 4 laps around the track. If each lap around the track is 0.25 miles long, and he starts and stops in the same locatio

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The answer is B) 0 miles. Because displacement is the shortest distance between starting point and ending point. Since, his starting point and ending point is the same, hence, his displacement is 0 miles.

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Alecsey [184]

Answer:

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3 years ago

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