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Nastasia [14]
3 years ago
15

Yesterday the temperature at noon was 15.1°F. By midnight, it had dropped by

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

-9.1 degrees at midnight

Step-by-step explanation:

15.1 - 24.2 = -9.1 degrees

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Which mathematician used the lengths of the chords created by the position of the Sun during the seasons to create a table of si
Nastasia [14]
I got this wrong...but it's Hipparchus.
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3 years ago
Read 2 more answers
Which statement correctly compares the spreads of the distributions?
swat32

Answer:

b. the ranges of penguin heights are the same.

Step-by-step explanation:

Hello!

Statements:

Which statement correctly compares the spreads of the distributions?

a. the mode of penguin heights at county side zoo is greater than  the mode at city view zoo.

b. the ranges of penguin heights are the same.

c. the range of penguin heights is greater at city view zoo than at  county side zoo.

d. the range of penguin heights is greater at county side zoo than at  city view zoo.

The mode and mean are measurements of central tendency, these indicate the position of a data set but don't show any information concerning the distribution of said data.

The range on the other had is a measurement of variance, it shows the difference between the maximum and minimum values of the data set and indicates its total dispersion.

City view Zoo R= 44-37= 7 cm

County side Zoo: R= 45-38= 7 cm

Both ranges are the same.

I hope this helps!

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
6 0
3 years ago
There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17
blondinia [14]

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

4 0
3 years ago
If trapezoid
agasfer [191]

Answer:

e (2,-1)

f (4,-1)

g (5,-4)

h (1,-4)

7 0
2 years ago
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