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4 years ago

A fan is marked up 40% on the original price. The original price was $20. What is the new price of the fan before sales tax?

Mathematics

1 answer:

JulsSmile [24]4 years ago

8 0

Answer:

$28

Step-by-step explanation:

40% of 20 is 8

20 + 8 = 28

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Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual has a Vis

ser-zykov [4K]

Answer:

a) $P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.45}= 0.667$

Represent the probability that the event B occurs given that the event A occurs first

b) $P(B'|A) = \frac{0.15}{0.45}=0.333$

Represent the probability that the event B no occurs given that the event A occurs first

c) $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.3}{0.35}= 0.857$

Represent the probability that the event A occurs given that the event B occurs first

d) $P(A'|B) = \frac{0.05}{0.35}=0.143$

Represent the probability that the event A no occurs given that the event B occurs first

Step-by-step explanation:

For this case we have the following probabilities given for the events defined A and B

$P(A) = 0.45, P(B) = 0.35, P(A \cap B) =0.30$

For this case we can begin finding the probability for the complements:

$P(B') =1-P(B) = 1-0.35= 0.65$

$P(A') =1-P(A) = 1-0.45= 0.55$

For this case we are interested on the following probabilities:

Part a

$P(B|A)$

For this case we can use the Bayes theorem and we can find this probability like this:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.45}= 0.667$

Represent the probability that the event B occurs given that the event A occurs first

Part b

$P(B'|A) = \frac{P(B' \cap A)}{P(A}$

And for this case we can find $P(B' \cap A) =P(A) -P(A\cap B)= 0.45-0.3=0.15$

And if we replace we got:

$P(B'|A) = \frac{0.15}{0.45}=0.333$

Represent the probability that the event B no occurs given that the event A occurs first

Part c

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.3}{0.35}= 0.857$

Represent the probability that the event A occurs given that the event B occurs first

Part d

$P(A'|B) = \frac{P(A' \cap B)}{P(B}$

And for this case we can find $P(A' \cap B) =P(B) -P(A\cap B)= 0.35-0.3=0.05$

And if we replace we got:

$P(A'|B) = \frac{0.05}{0.35}=0.143$

Represent the probability that the event A no occurs given that the event B occurs first

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3 years ago

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jasenka [17]

The answer is monomial

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Answer:

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Step-by-step explanation:

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3 years ago

What is 10 divied by 7/8

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Answer:

11.43

Step-by-step explanation:

10 divided by 7/8

Set the expression:

(10/(7/8))

To solve, flip the denominator fraction, and make the division into multiplication:

((10 x 8)/7)

Multiply across, then divide:

(80)/7

Divide:

80/7 = 11.43 (rounded)

11.43 is your answer.

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Answer:

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