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3 years ago

How to find zeroes in intercept form y=4x^2-19x-5

Mathematics

1 answer:

Sliva [168]3 years ago

3 0

I hope this helps you

y= 4x^2-19x-5

4x +1

x -5

y=(4x+1). (x-5)

4x+1=0 4x= -1 x= -1/4

x-5=0 x= 5

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RSTU is a parallelogram. Solve for x. ANSWERS: A) –5 B) 10 C) 8 D) 0

nirvana33 [79]

Answer:

D) 0

Step-by-step explanation:

In a ║gm, opposite sides are parallel and equal.

So,

RS = UT

=> x+5 = 2x+5

=> 2x-x = 5-5

=> 2x = 0

=> x = 0

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3 years ago

How do you convert something like 3000mm to km if 1 km equals 1000m? btw - im in elementary - but there's no option for that is

FrozenT [24]

Answer:

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3 years ago

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the normal distribution and the central limit theorem, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is 1 subtracted by the p-value of Z when X = 670, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{670 - 660}{9}$

$Z = 1.11$

$Z = 1.11$ has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the normal distribution and the central limit theorem, you can take a look at brainly.com/question/24663213

7 0

2 years ago

46 is 92 percent of what number

Vladimir79 [104]

1. We assume, that the number 92 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for. 
3. If 100% equals 92, so we can write it down as 100%=92. 
4. We know, that x% equals 46 of the output value, so we can write it down as x%=46. 
5. Now we have two simple equations:
1) 100%=92
2) x%=46
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=92/46
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 46 is what percent of 92

100%/x%=92/46
(100/x)*x=(92/46)*x - we multiply both sides of the equation by x
100=2*x - we divide both sides of the equation by (2) to get x
100/2=x 
50=x 
x=50

now we have: 
46 is 50% of 92

I hope this helps!

5 0

3 years ago

18% commission on a $500 couch bro can someone pleaseee help me

madam [21]

Um Hi It is $90 so type $90

3 0

3 years ago