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Zielflug [23.3K]
3 years ago
10

How to find zeroes in intercept form y=4x^2-19x-5

Mathematics
1 answer:
Sliva [168]3 years ago
3 0
I hope this helps you



y= 4x^2-19x-5


4x +1


x -5


y=(4x+1). (x-5)



4x+1=0 4x= -1 x= -1/4


x-5=0 x= 5
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Answer:

Below

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7 0
3 years ago
Read 2 more answers
Can someone plzz help​
tankabanditka [31]

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6 0
4 years ago
What's 8n-(2n-3)=12?
Alborosie
8n- (2n-3) =12
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Hope this helps :)
6 0
3 years ago
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