How to find zeroes in intercept form y=4x^2-19x-5

1 answer:

3 0

I hope this helps you

y= 4x^2-19x-5

4x +1

x -5

y=(4x+1). (x-5)

4x+1=0 4x= -1 x= -1/4

x-5=0 x= 5

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kvasek [131]

Answer:

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