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Rudik [331]
3 years ago
15

I'll give brainliest PLZZZ!

Mathematics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

x= 3. y = 3

Step-by-step explanation:

-3x + 7y = 12. #1

x - 2y = -3. #2

Multiply Eqtn #2 by 3 and add the two together:

-3x + 7y = 12

3x - 6y = -9

or. y = 3

Plug this value into Eqtn #2 and you'll get

x = 3

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Find the exact volume of the cylinder.
netineya [11]

Step-by-step explanation:

The volume of a cylinder can be found with the equation

<em><u>\pi{r}^{2}h</u></em>

So, plug in the values. The diameter of the circle is 10m, which means that the radius is 5m. The height of the cylinder is 13m.

V = π (5)^2 (13)

<u>V = 325π m^3</u>

Answer:

D. 325π m^3

4 0
3 years ago
Read 2 more answers
the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se
swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0
2 years ago
Find the equation of the circle whose center and radius are given.
trapecia [35]
(x – h)² + (y – k)²<span> = r</span>² 

Fill in the numbers 

(x – 7)²<span> + (y +3)</span>²<span> = 49</span>
6 0
3 years ago
Read 2 more answers
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
angela and neil are going to the movies they each bought a medium popcorn and neil got a small soft drink angela had a $10 gift
bazaltina [42]
$5.90 is my answer because its 19.3-9-4.4


6 0
3 years ago
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