1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vaieri [72.5K]
3 years ago
5

Which size can of green beans shown in the table has the lowest unit price? ​

Mathematics
2 answers:
tino4ka555 [31]3 years ago
6 0
The answer is 8 ounces.
malfutka [58]3 years ago
3 0

Answer:

probably the 8 ounce one

Step-by-step explanation:

You might be interested in
Plz be spefic and tell me step by step with answer
Alexxandr [17]
What is the problem?
6 0
3 years ago
1. Write an algebraic expression to represent each verbal phrase.
pantera1 [17]

Answer:

a) p+2

b) 193x+19

c) 18 - a÷b

8 0
3 years ago
Rationalize the denominator and simplify.
cestrela7 [59]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3151018

——————————
 
     \mathsf{\dfrac{3\sqrt{6}+5\sqrt{2}}{4\sqrt{6}-3\sqrt{2}}}


Multiply and divide by the conjugate of the denominator, which is  \mathsf{4\sqrt{6}+3\sqrt{2}:}

     \mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}}


Expand those products and eliminate the brackets:
 
     \mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(3\sqrt{6}+5\sqrt{2}\big)\cdot 3\sqrt{2}}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(4\sqrt{6}-3\sqrt{2}\big)\cdot 3\sqrt{2}}}\\\\\\ \mathsf{=\dfrac{12\cdot \big(\sqrt{6}\big)^2+20\sqrt{2}\cdot \sqrt{6}+9\cdot \sqrt{6}\cdot \sqrt{2}+15\cdot \big(\sqrt{2}\big)^2}{16\cdot \big(\sqrt{6}\big)^2-12\cdot \sqrt{2}\cdot \sqrt{6}+ 12\cdot \sqrt{6}\cdot \sqrt{2}-9\cdot \big(\sqrt{2}\big)^2}}\\\\\\ \mathsf{=\dfrac{12\cdot 6+20\sqrt{2\cdot 6}+9\sqrt{6\cdot 2}+15\cdot 2}{16\cdot 6-12\sqrt{2\cdot 6}+ 12\sqrt{6\cdot 2}-9\cdot 2}}\\\\\\ \mathsf{=\dfrac{72+20\sqrt{12}+9\sqrt{12}+30}{96-12\sqrt{12}+12\sqrt{12}-18}}

     \mathsf{=\dfrac{72+29\sqrt{12}+30}{96-18}}\\\\\\ \mathsf{=\dfrac{102+29\sqrt{2^2\cdot 3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot \sqrt{2^2}\cdot \sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot 2\sqrt{3}}{78}} 

     \mathsf{=\dfrac{102+58\sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{\,\diagup\!\!\!\! 2\cdot \big(51+29\sqrt{3}\big)}{\diagup\!\!\!\! 2\cdot 39}} 

     \mathsf{=\dfrac{51+29\sqrt{3}}{39}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

4 0
3 years ago
The cost of 200 gallons of fuel oil is 425.52.This includes an 8% tax.What is the cost of 1 gallon of oil before the tax is adde
Evgesh-ka [11]

Answer:

look on m a t h w a y

Step-by-step explanation:

7 0
3 years ago
Pls help will give brainliest
ICE Princess25 [194]

answer: area=b18ft×h13ft

Step-by-step explanation:

area=base×height

3 0
3 years ago
Other questions:
  • 400% of what number is 80?
    8·2 answers
  • Beth looked through an old
    11·1 answer
  • A soft-drink machine is regulated so that the amount of drink dispensed is approximately normally distributed with standard devi
    9·2 answers
  • The percentage of titanium in an alloy used in aerospace castings is measured in 51 randomly selected parts. The sample standard
    10·1 answer
  • Ethan needs to save at least $500 to purchase a new dirt bike. So far, he has saved $175. If he hopes to use two-fifths of his n
    11·2 answers
  • 10 less than the product of
    12·2 answers
  • Help on these problems please for my test ​
    10·1 answer
  • What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
    15·2 answers
  • Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample
    6·1 answer
  • What is the angle measure of an arc bounding sector with an area of 5pie square miles?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!