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Alenkinab [10]
3 years ago
9

What is £41 deacreased by 90%?

Mathematics
2 answers:
DaniilM [7]3 years ago
7 0
90% of <span>£41 = 90/100 × 41 = </span><span>£36.9

</span>£41 decreased by 90% = 41 - 36.9 = <span>£4.1</span>
kirill [66]3 years ago
5 0
£41 ÷ 100 = £0.41
£0.41 × 10 = £4.1
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The first three steps for solving the quadratic equation by completing the square are shown. Fill in the missing number in the l
Oksi-84 [34.3K]

The first three steps for solving the quadratic equation by completing the square are as follows;

1. \rm 9x^2 +54x = 7

2. \rm 9(x^2 + 6x) = 7

3. \rm 9(x^2 + 6x + 9) = 7 + 81

Given

The quadratic equation given as  9x^2 + 54x = 7.

<h3>Quadratic equation;</h3>

The highest power of the degree is 2 is known as a quadratic equation.

To solve using the completing the square method.

The first three steps for solving the quadratic equation by completing the square are given below.

1. Write the equation in a way that the constants are on the right side while the terms with x are on the left.

\rm 9x^2 +54x = 7

2. Make sure that the coefficient of the x^2 term is 1.

\rm 9(x^2 + 6x) = 7

3. Adding a term to both sides that will complete the square on the left side.

This is done by dividing the coefficient of the x term by 2 and squaring it.

The same amount should be added to the right side to balance the equation.

\rm 9(x^2 + 6x + 9) = 7 + 81

To know more about quadratic equations click the link given below.

brainly.com/question/25963825

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2 years ago
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7 0
4 years ago
Identify and explain the causes of WW1
saveliy_v [14]
The direct cause of WWI was the assassination of Archduke Franz Ferdinand at Sarajevo on 28 June 1914. However historians feel that a number of factors contributed to the rivalry between the Great powers that allowed war on such a wide-scale to break out.

7 0
3 years ago
What is the solution of the system?
kakasveta [241]

Divide the first equation by 2 and add the result to the second equation. This will eliminate x.

... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)

... 3y = -18 . . . . . collect terms

... y = -6 . . . . . . . divide by 3

Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.

... 2x +4(-6) = -12

... 2x = 12 . . . . . . . . add 24

... x = 6 . . . . . . . . . . divide by 2

The solution is (x, y) = (6, -6).

8 0
4 years ago
What is the sum of the series? 4 ∑k=1 (2k^2−4)
larisa86 [58]

The sum of the series \sum_{k=1}^{4}\left(2 k^{2}-4\right) is 44.

Step-by-step explanation:

The given series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

To find the sum of the series, we need to substitute the values for k in the series.

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]

Now, simplifying the square terms, we get,

[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]

Multiplying the terms,

[2-4]+[8-4]+[18-4]+[32-4]

Subtracting the values within the bracket term, we get,

-2+4+14+28

Now, adding all the terms, we get the sum of the series,

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

Thus, the sum of the series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

8 0
3 years ago
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