The first three steps for solving the quadratic equation by completing the square are as follows;
1. 
2. 
3. 
Given
The quadratic equation given as 9x^2 + 54x = 7.
<h3>Quadratic equation;</h3>
The highest power of the degree is 2 is known as a quadratic equation.
To solve using the completing the square method.
The first three steps for solving the quadratic equation by completing the square are given below.
1. Write the equation in a way that the constants are on the right side while the terms with x are on the left.

2. Make sure that the coefficient of the x^2 term is 1.

3. Adding a term to both sides that will complete the square on the left side.
This is done by dividing the coefficient of the x term by 2 and squaring it.
The same amount should be added to the right side to balance the equation.

To know more about quadratic equations click the link given below.
brainly.com/question/25963825
B beacuse it’s 173 thanks very much
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Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
The sum of the series
is 44.
Step-by-step explanation:
The given series is 
To find the sum of the series, we need to substitute the values for k in the series.
![\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]](https://tex.z-dn.net/?f=%5Csum_%7Bk%3D1%7D%5E%7B4%7D%5Cleft%282%20k%5E%7B2%7D-4%5Cright%29%3D%5Cleft%5B2%281%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%282%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%283%29%5E%7B2%7D-4%5Cright%5D%2B%5Cleft%5B2%284%29%5E%7B2%7D-4%5Cright%5D)
Now, simplifying the square terms, we get,
![[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]](https://tex.z-dn.net/?f=%5B2%281%29-4%5D%2B%5B2%284%29-4%5D%2B%5B2%289%29-4%5D%2B%5B2%2816%29-4%5D)
Multiplying the terms,
![[2-4]+[8-4]+[18-4]+[32-4]](https://tex.z-dn.net/?f=%5B2-4%5D%2B%5B8-4%5D%2B%5B18-4%5D%2B%5B32-4%5D)
Subtracting the values within the bracket term, we get,

Now, adding all the terms, we get the sum of the series,

Thus, the sum of the series is 