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3 years ago

What is £41 deacreased by 90%?

Mathematics

2 answers:

DaniilM [7]3 years ago

7 0

90% of £41 = 90/100 × 41 = £36.9

£41 decreased by 90% = 41 - 36.9 = £4.1

kirill [66]3 years ago

5 0

£41 ÷ 100 = £0.41
£0.41 × 10 = £4.1

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What does 59% divide by 4 times 8 minus 9 times 5 equal?

Triss [41]

Answer: -43.82

Step-by-step explanation:

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3 years ago

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Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

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3 years ago

The length of a planet's orbit around a star is approximately 17,650,000 km.

daser333 [38]

Answer:

1150 km/hr

Step-by-step explanation:

Formula for Average Speed is given as = Distance in Kilometers/ Time in Hours

In the question we are given the following parameters.

The length of a planet's orbit around a star = Distance = 17,650,000 km.

Time taken to complete a full orbit = 640 Earth days

Step 1

We need to convert the time in days to hours

1 Earth day = 24 hours

640 Earth days =

We cross multiply

640 Earth days × 24 hours

= 15360 hours.

Step 2

Average Speed = Distance in Kilometers/ Time in Hours

Average Speed = 17,650,000 km. /15360 hours

Average Speed = 1149.0885417 km/hr

Approximately to 3 significant figures=

1150 km/hr

Therefore, the planets average speed in kmh-1 to 3sf is 1150 km/hr

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3 years ago

1. Thom has a scale model of his car. The

MariettaO [177]

$x =\frac{4}{3}inch$ is the size in wheels on the scale model .

Step-by-step explanation:

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ $\frac{1}{12} = \frac{x}{16}$ { x is size of wheel in scale model }

⇒ $\frac{1(16)}{12} = \frac{x}{16}(16)$

⇒ $x =\frac{16}{12}$

⇒ $x =\frac{4}{3}inch$

Therefore , $x =\frac{4}{3}inch$ is the size in wheels on the scale model .

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3 years ago

1. (05.06 MC)

adoni [48]

Part A: it is linear because it is not curving and it consists of straight lines.

Part B: in side A it is increasing because it has a positive slope. In side b it is constant because the slope is 0 since it is straight. Finally, side C is decreasing because the slope is negative.

Part C: during side A the ant is crawling out of the hole in 2 seconds. After that, the ant stops for 2 more seconds as shown in side B. Then, he crawls back into the hole as shown by the decrease in distance due to the slope.

Hope this helps!!!

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3 years ago