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Leokris [45]
3 years ago
5

Paula has a box in the shape of a rectangular prism. The box has a length of 40 inches, a height of 24 inches, and a width of 18

inches. What is the volume of the box
Mathematics
2 answers:
zepelin [54]3 years ago
6 0

Answer:

17,280 in^3 (cubic inches)

Step-by-step explanation:

40(L)x24(H)x18 (W)

Rom4ik [11]3 years ago
4 0

Answer:

17,388 in^3

Step-by-step explanation:

To find the volume of a box, use this formula: V = lwh

We are given the length, height, and width in the problem. Plug these values into the formula.

l = 40 in

h = 24 in

w = 18 in

V = (40) (18) (24) = 17,338

So, the volume of the box is 17,388 in^3.

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Anastaziya [24]
<span>C/4-5=4
Add 5 to both sides
C/4=9
Multiply 4 on both sides
Final Answer: C=36</span>
3 0
3 years ago
Read 2 more answers
Which conditional statement has a false converse?
exis [7]

Consider the converses:

a) If two planes have no points in common, then they are parallel. (true)

b) If a point lies on the y-axis, then it has x-coordinate 0. (true)

c) If two angles have the same measure, then they are congruent. (true)

d) If a figure has four sides, then it is a square. (FALSE) (A figure with 4 sides may not even be a plane figure.)

8 0
4 years ago
Graph the function and identify all key characteristics f(x)=x^3-12x^2+45x-54
damaskus [11]

Answer:

We kindly ask you to see the explanation and the image attached below for further details.

Step-by-step explanation:

From Function Theory we know that third order polynomials are continuous functions with one relative minimum and one relative maximum and whose domain and range comprehends the set of all real numbers. Since the leading coefficient of the polynomial is positive, then two increasing intervals and only one increasing interval exist.

Now we proceed to graph the function and label each relevant information when possible.

Domain

Dom \{f(x)\} = \mathbb{R}

Range

Ran \{f(x)\} = \mathbb{R}

Zeros

x = 3 and x = 6

8 0
3 years ago
Question 4
astraxan [27]

Answer:

No real roots

Step-by-step explanation:

The given equations are:

3x-1+2y=0

3x^2-y^2+4=0

We make y the subject in the first equation to get

y=\frac{1-3x}{2}

We substitute into the second expression to get:

3x^2-(\frac{1-3x}{2})^2+4=0

We expand to get:

3x^2-\frac{(1-6x+9x^2)}{4}+4=0

Multiply through by 4 to get:

12x^2-1+6x-9x^2+16=0

3x^2+6x+15=0

The discriminant is given by D=b^2-4ac

D=3^2-4*12*15

D=-711

Since the discriminant is less than zero, the two curves never intersects.

Therefore the system has no real roots

6 0
4 years ago
In △ABC, points M and P are points on sides AC and BC respectively. Find the area of △MPC, if BM∩AP=O, AAOM=45 dm2, ABOP=15 dm2,
aniked [119]

First calculate the Area of MOP by using congruent altitudes.

(Area MOP)/(Area AOM) = PO/OA = (Area BOP)/(Area AOB)

Area MOP = (Area AOM)*(Area BOP)/(Area AOB) = (45)*(15/75) = 9.

Now, let Area CMP = x. And use two sets of triangles with congruent altitudes.

(Area CMP)/(Area BMP) = x/(9+15) = x/24 = (CP)/(BP).

(Area CAP)/(Area BAP) = (x+54)/90 = (CP)/(BP)

So,

(Area CMP)/(Area BMP) = (Area CAP)/(Area BAP)

or

x/24 = (x+54)/90

90x = 24 (x+54) = 24x + 1296

66x = 1296

x = 19 \frac{7}{11}

8 0
4 years ago
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