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Komok [63]
3 years ago
12

The school choir is selling fruit boxes to earn money for new robes. The fruit boxes sell for $30

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

the answer is c

Step-by-step explanation:                    

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PLEASE NO LINKS.
Kamila [148]

Answer:

Step-by-step explanation:

Sustituye la variable  

y

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x

+

2

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−

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x

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en la expresión.

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3 0
3 years ago
Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x ≥ 72)?
Zina [86]

Approximately 65% of the distribution lies within one standard deviation of the mean, which is to say,

P(72 ≤ x ≤ 86) ≈ 0.65

Normal distributions are symmetric, so the percentage of values one standard deviation below the mean is equal to the percentage of values one standard deviation above the mean.

P(72 ≤ x ≤ 79) = P(79 ≤ x ≤ 86)

but since the sum of these make up P(72 ≤ x ≤ 86), we find

P(72 ≤ x ≤ 79) ≈ 0.65/2 = 0.325

Also due to symmetry, exactly half of the distribution lies to either side of the mean; namely,

P(x ≥ 79) = 0.5

It follows that

P(x ≥ 72) = P(72 ≤ x ≤ 79) + P(79 ≤ x)

P(x ≥ 72) = 0.325 + 0.5

P(x ≥ 72) = 0.825 ≈ 0.84

8 0
3 years ago
The best interest rate for a borrower on a $5,000 loan for 5 years is:
Gennadij [26K]

Answer:

So, $83.40 should be paid monthly

Step-by-step explanation:

5000 divided by 5 = 1000

1000 should be paid yearly

1000 divided by 12 = 83.40

12 represents the number of months in a year.

3 0
3 years ago
Read 2 more answers
HELP ASAP <br> H(x)=-6x+8<br> G(x)=10-2x<br><br> H(G(x))
galben [10]

<u>Answer:</u>

H(G(x)) = 12x - 52

<u>Step-by-step explanation:</u>

We are given the following two functions:

H ( x ) = - 6 x + 8

G ( x ) = 1 0 - 2 x

And we are to find the value of H(G(x)).

For that, we will apply the function of H on the function of G.

H(G(x))=H(10-2x)

H ( G ( x ) ) = - 6 ( 1 0 - 2 x ) + 8

H(G(x))=-60+12x+8

H(G(x)) = 12x - 52

7 0
3 years ago
Given that the f(y) = y - 1 and g(y) = y^3 - 2y - 1, find (gof) (y)I and hence, (gof) (-6).
nordsb [41]

(g \circ f)(y)=(y-1)^3-2(y-1)-1\\(g \circ f)(y)=y^3 - 3 y^2 + 3 y - 1-2y+2-1\\(g \circ f)(y)=y^3 - 3 y^2 +y\\\\(g \circ f)(-6)=(-6)^3-3\cdot(-6)^2+(-6)\\(g \circ f)(-6)=-216-108-6\\(g \circ f)(-6)=-330

3 0
3 years ago
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