1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr Goodwill [35]
3 years ago
9

Solve for x...............

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

x=17

Step-by-step explanation:

Hello There!

The shown figure is a 6 sided figure and if you didn't know the interior angles of a 6 sided figure add up to equal 720

so

720=110+8x-1+5x+36+116+7x+19+6x-2

now we solve for x

step 1 combine like terms

110-1+36+116+19-2=278

8x+5x+7x+6x=26x

now we have

720=278+26x

step 2 subtract 278 from each side

720-278=442

we now have

442=26x

step 3 divide each side by 26

442/26=17

we're left with

x=17

You might be interested in
What is 1 4/7 divided by 4 5/7<br> ANSWER THIS ASAP I ONLY HAVE 57 minutes LEFT PLEASE HURRY!!!!
kodGreya [7K]

Answer:

Step-by-step explanation:

\frac{11}{7} * \frac{7}{33}

\frac{11 * 7}{7 * 33}

\frac{1}{3}

0.333

4 0
4 years ago
How do you determine the area under a curve in calculus using integrals or the limit definition of integrals?
RSB [31]

Answer:

Please check the explanation.

Step-by-step explanation:

Let us consider

y = f(x)

To find the area under the curve y = f(x) between x = a and x = b, all we need is to integrate y = f(x) between the limits of a and b.

For example, the area between the curve y = x² - 4 and the x-axis on an interval [2, -2] can be calculated as:

A=\int _a^b|f\left(x\right)|dx

    = \int _{-2}^2\left|x^2-4\right|dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx

   =\int _{-2}^2x^2dx-\int _{-2}^24dx

solving

\int _{-2}^2x^2dx

\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1

   =\left[\frac{x^{2+1}}{2+1}\right]^2_{-2}

    =\left[\frac{x^3}{3}\right]^2_{-2}

computing the boundaries

     =\frac{16}{3}

Thus,

\int _{-2}^2x^2dx=\frac{16}{3}

similarly solving

\int _{-2}^24dx

\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax

     =\left[4x\right]^2_{-2}

computing the boundaries

      =16

Thus,

\int _{-2}^24dx=16

Therefore, the expression becomes

A=\int _a^b|f\left(x\right)|dx=\int _{-2}^2x^2dx-\int _{-2}^24dx

  =\frac{16}{3}-16

  =-\frac{32}{3}

  =-10.67 square units

Thus, the area under a curve is -10.67 square units

The area is negative because it is below the x-axis. Please check the attached figure.

   

6 0
3 years ago
YO YO YO WSG…QUESTION AND POINTS OF THE DAY.
NISA [10]

Answer:

my fav food is Pizza

4 0
3 years ago
Read 2 more answers
The function h(x) is defined as shown.
Ierofanga [76]

9514 1404 393

Answer:

  (b)  h(x) ≤ 5

Step-by-step explanation:

The maximum vertical extent of the graph is h(x) = 5 at x = 3. The range is all values of h(x) less than or equal to that:

  h(x) ≤ 5

3 0
3 years ago
Read 2 more answers
A girl's feet are negative 2 over 4 yards from the surface of a pool. A boy's feet are negative 3 over 4 yards from the surface
frozen [14]
The girls are closer. Her feet are 1/2 the distance away from the surface pool, the boys are 3/4 away.
6 0
3 years ago
Other questions:
  • (15+23)+7=15+(46+7)<br><br> Is 46 right
    5·1 answer
  • PLEASE PLEASE PLEASE HELP MEEEEE
    13·1 answer
  • Mrs. Martin is making ice cream cones for her family. She has 2.25 cups of ice cream and puts equal amounts of ice cream in each
    15·2 answers
  • 4.6p – 6.3p + 3.9 = –9.18
    6·2 answers
  • Solve the equation by completing the square
    7·1 answer
  • An employee works 22 days
    10·1 answer
  • Find the values the thing like beta
    13·1 answer
  • The square below represents one whole.
    15·1 answer
  • Please help me !
    7·1 answer
  • What is 0.6% as a fraction in simplest form
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!