3 years ago

What is the quotient of 3x2-16x+12 and x-3

Mathematics

1 answer:

kirill115 [55]3 years ago

5 0

The answer to your question is D.

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Casey paid $32 for a book that was on a sale at 20% off. What was the original price for that book?

Elis [28]

Answer:

$40

Step-by-step explanation:

If it was 20% off, you are paying 80% of the original price.

So .80 * Original price = $32

32/.8 = 40

8 0

3 years ago

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2 MULTIPLE CHOICES! 75 POINTS!!! EASY!!

Leno4ka [110]

Answer:

Step-by-step explanation:

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3 years ago

Please help me with part b of this question. THanks.

nevsk [136]

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3 years ago

What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

$-5x^{2} +5=-5$

$-5x^{2}=-10$

$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

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3 years ago

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Place the grouping symbols to make this equation true. 84-48/8-4=72

vlabodo [156]

84-6-4=72
48/4=12. 84-12= 72
84 - (48/(8-4)) = 84 - (48/4) -4 = 72
84 - 12 = 72

4 0

3 years ago