I know m=2.25 and n=8.6 but I don't know about q.
Answer:
Step-by-step explanation:
You can readily see from the diagram, above, that the side length of the middle cube will be between 3 and 4. You want to determine to the nearest hundredth what value between 3 and 4 represents the side length of the cube whose volume is 45 units^3.
Please note: the middle cube has been mislabeled. Instead of volume = 30 units^3, the volume should be 45 units^3.
Here's the procedure:
Guess an appropriate s value. Let's try s = side length = 3.5
Cube this: (3.5 units)^3 = 42.875. Too small. Choose a larger possible side length, such as 3.7: 3.7^3 = 50.653. Too large.
Try s = 3.6: 3.6^3 = 46.66. Too large.
Choose a smaller s, one between 3.5 and 3.6: 3.55^3 = 44.73. This is the best estimate yet for s. Continue this work just a little further. Try s = 3.57. Cube it. How close is the result to 45 cubic units?
Answer:
x = 7
Step-by-step explanation:
Rearrange the equation to make x the subject.
Original:
7x + 3 = 52
subtract 3 from both sides
7x = 52 -3
7x = 49
Divide both sides by 7
x = 49/7
x = 7
Answer: 6 inches long and 4 inches wide
Step-by-step explanation: The dimensions of the actual crate are 20 times those on Jacob's drawing. The dimensions on the builder's drawing are 1/10 of those, so (1/10)(20) = 2 times the dimensions on Jacob's drawing.
hope this helps
I’m sorry but the picture is black.
