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Alika [10]
4 years ago
7

Question 1*

Mathematics
1 answer:
worty [1.4K]4 years ago
6 0

Given expressions;

     f(x) = x² + 6x + 7

     g(x) = 8x² - 2

     h(x) = 3x + 4

     k(x) = x - 3

Find  f(2) - g(2). k(2)

f(2) = 2² + 6(2) + 7 = 23

g(2) = 8(2)² - 2 = 30

k(2) = 2 - 3 = -1

Now,  f(2) - g(2). k(2) = 23  - (30)(-1)

                                  = 53

The solution to the problem is 53

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Stella [2.4K]

We know that 12 out of 30 employees said they work overtime on a regular basis. If we assume that this sample represents well all the employees, we can extend this proportion to all employees:

12\div 30 = x \div 200 \iff x = \dfrac{12\cdot 200}{30} = 80

So, if 12 out of 30 randomly selected employees said they work overtime on a regular basis, we assume that 80 out of all the 200 employees work overtime on a regular basis.

Note that this is a strong assumption: in the worst case, there are 12 employees working overtime, and we have been unlucky to pick them all in our sample.

Anyway, if our assumption is correct, knowing that 80 out of 200 employees work overtime on a regular basis leads to a percentage of

\dfrac{80}{200}=\dfrac{40}{100}=40\%

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Help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Dafna11 [192]

If f(x)= 3x+2 and g(x)= 4x, then

f(x)+g(x) = 3x+2+4x

= 7x+2

For f(g(x)), you work from the inside and work your way out. Another way of thinking is to go from right to left. (Inside/out and right/left are the same simply using different wording).

So what is g(x)? 4x.

Now, you take 4x and plug it into the f(x).

** Math--> English translation:

Look at the f(x) equation. Wherever you see an x in the f(x), replace the x with 4x [because 4x is the g(x)]. Basically, plug the g(x) into f(x).

So:

f(g(x)) becomes

f(4x) becomes

3 (4x)+2 = 12x+2

** Disclaimer: Notation may be inaccurate.

That's your answer. (Usually you leave it as so, but if your instructor wants it factored, then proceed).

As for the third part, I am unsure of a clear answer, so I am unable to provide an answer at the time.

**********************

Hope that helped.

DISCLAIMER:

Always double check with a reliable source, as mistakes are a possibility. Never use this, or any, platform to cheat.

6 0
3 years ago
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