Answer:
4 meters.
Step-by-step explanation:
We have been given that a mover uses a ramp to pull a 1000 n cart up-to the floor 0.8 meters high. It takes a force of 200 newtons to pull the cart. We are asked to find the length of the ramp.
We will use following formula to answer our given problem.
![\text{Force}\times \text{Ramp length}= \text{Weight}\times\text{Height}](https://tex.z-dn.net/?f=%5Ctext%7BForce%7D%5Ctimes%20%5Ctext%7BRamp%20length%7D%3D%20%5Ctext%7BWeight%7D%5Ctimes%5Ctext%7BHeight%7D)
![200\text{N}\times \text{Ramp length}=1000\text{N}\times 0.8\text{m}](https://tex.z-dn.net/?f=200%5Ctext%7BN%7D%5Ctimes%20%5Ctext%7BRamp%20length%7D%3D1000%5Ctext%7BN%7D%5Ctimes%200.8%5Ctext%7Bm%7D)
![200\text{N}\times \text{Ramp length}=800\text{Nm}](https://tex.z-dn.net/?f=200%5Ctext%7BN%7D%5Ctimes%20%5Ctext%7BRamp%20length%7D%3D800%5Ctext%7BNm%7D)
![\text{Ramp length}=\frac{800\text{Nm}}{200\text{N}}](https://tex.z-dn.net/?f=%5Ctext%7BRamp%20length%7D%3D%5Cfrac%7B800%5Ctext%7BNm%7D%7D%7B200%5Ctext%7BN%7D%7D)
![\text{Ramp length}=4\text{m}](https://tex.z-dn.net/?f=%5Ctext%7BRamp%20length%7D%3D4%5Ctext%7Bm%7D)
Therefore, the length of the ramp would be 4 meters.
Answer:
$925,000
Step-by-step explanation:
Let "t" represent "total sales."
We are asking how much this person must bring in thru sales to end up with $55,000 in earnings.
A suitable equation would be:
$18,000 + 0.04t = $55,000.
Let's isolate t. Start by subtracting $18,000 from both sides, obtaining:
0.04t = $37,000
Dividing both sides by 0.04 results in t = $925,000.
Her sales must be $925,000 for her income (including earnings) to be $55,000.
Answer:
The amount after 1 year is $ 1060 .
Step-by-step explanation:
The amount after 1 year on $1,000 invested at 6% per year on simple interest
is given by,
$ ![1000 \times (1 + \frac{6}{100})](https://tex.z-dn.net/?f=1000%20%5Ctimes%20%281%20%2B%20%5Cfrac%7B6%7D%7B100%7D%29)
= $ (1000 + 60)
= $ 1060
We know that, if,
Principal = P unit
Rate of annual simple interest = R%
Time = T year
then, amount, A =
unit
<span>The first group is 5 - 9, the second group is 10 - 14 and the third group is 15 - 19. We now find the number of data within the interval 15 - 19. In the given frequency distribution, 17, 15, 18, 19, 19 and 16 are within the interval 15 - 19. Therefore, the frequency of the third group is 6.</span>
Answer:
-1.13
Step-by-step explanation: