3 years ago

Can someone help me please

1 answer:

5 0

I don’t see nothing there

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jolli1 [7]

Given the quadratic equation:

$x^2+5x-5=0$

Using the general solution for quadratic equations:

$ax^2+bx+c=0\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

From the problem, we identify:

$\begin{gathered} a=1 \\ b=5 \\ c=-5 \end{gathered}$

Then:

$x=\frac{-5\pm\sqrt{25+20}}{2}=\frac{-5\pm3\sqrt{5}}{2}$

And the solution set is:

$\lbrack\frac{-5-3\sqrt{5}}{2},\frac{-5+3\sqrt{5}}{2}]$

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