There are 25 $10 bills and 11 $20 bills.
Step-by-step explanation:
Given,
Worth of proceeds from garage = $470
Let,
x be the number of $10 bills
y be the number of $20 bills.
According to given situation;
10x+20y=470 Eqn 1
x = y+14 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 30

Putting y=11 in Eqn 2

There are 25 $10 bills and 11 $20 bills.
Keywords: linear equation, substitution method
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15, 20, 25 is the correct answer
Answer:
p= 3
q= 7
Hope this helps :)
Answer:
- 4
Step-by-step explanation:
The conjugate of - 2 + i is - 2 - i, thus
- 2 + i + (- 2) - i
= - 2 + i - 2 - i ← collect like terms
= - 4 ← in the form a + bi with b = 0
3x+2y=11--------x1
7x-y=3------------x2
3x+2y=11---equ 1
14x-2y=6---equ 2
equ 1+ equ 2 will eliminate y
17x=17
x=1
then put x=1 in equ 1
3(1)+2y=11
2y=11-3
2y=8
y=8/2
y=4