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DENIUS [597]
3 years ago
9

Find the side length of X

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0

Answer:

7√3

Step-by-step explanation:

We can use pythagoreans theorem to solve this

Since, we know one side, and the hypotenuse, we can solve for the other side.  

Pythagoreans theorem: a²+b²=c²

Where a and b are two sides, and c is the hypotenuse (the side opposite of the right angle)

In this triangle, 7 is the side, and 14 is the hypotenuse.

I will plug in the values into pythagoreans theorem, and then simplify:

a^{2}+b^{2} =c^{2} \\\\7^{2} +x^{2} =14^{2} \\\\49+x^{2} =196\\\\x^{2} =147\\\\x=\sqrt{147} \\\\x=\sqrt{49*3 }\\\\ x=\sqrt{7^{2} *3 }\\\\x=7\sqrt{3}

So x = 7√3

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Isaiah And Cooper work at a dry cleaner Ironing shirts.isaiah can iron 25 shirts per hour, and Cooper can iron 30 shirts per hou
neonofarm [45]

Answer:

Step-by-step explanation:

340/25 = 13.6 = 13 hours and 10 min

30 x 13.6 = 408 hours

25x+30y= 340 and y=2x can be used to determine the number of hours cooper worked and the number of hours isaiah worked. Where x Isaiah 's working hours and y is cooper's working hours.

Step-by-step explanation:

Isaiah ironing rate per hour = 25 shirts

Cooper ironing rate per hour = 30 shirts

Total shirts pressed = 340

Let,

Isaiah´s number of hours = x

Cooper's number of hours = y

According to given statement;

25x+30y=340   Eqn 1

Hudson worked twice many hours as grace.

y = 2x    Eqn 2

Keywords: linear equations, variables

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brainly.com/question/4805611

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8 0
4 years ago
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In order to test a hypothesis, the variable that the scientist changes to a predetermined value is known as _________________. i
eimsori [14]
The controlled variable
8 0
4 years ago
Find the greatest common factor of the following monomials gh2 2g3h
anzhelika [568]
Hey there :)

gh² and 2g³h

The common here are g and h because the factor g and h appear in both terms

Therefore, the GCF is gh

5 0
3 years ago
A. Lin is using the diagram to prove the statement, "If a parallelogram has one
BigorU [14]

The congruence of the angles and triangles are proven as follows;

a. The composition angles of FGH are alternate interior angles to the composition angles of angle AHEF

b. The three sides of triangle ∆EHG are congruent to the three sides of triangle ∆GFE, therefore, triangles ∆EHG and ∆GFE are congruent by SSS congruency rule

<h3>What are congruent triangles?</h3>

The lengths of the three sides of triangles that are congruent.

a. The shape of quadrilateral EFGH = A parallelogram

The measure of angle HEF = 90°

Angle HEF = 90°

Angle HEF = Angle HED + Angle DEF

Angle HED is congruent to angle FGD (Alternate interior angles theorem)

Angle HED = angle FGD

Angle DEF is congruent to angle DGH (Alternate interior angles theorem)

Angle DEF = angle DGH

Angle FGH = Angle FGD + Angle DGH

Angle FGH = Angle HED + Angle DEF (Substitution property)

Angle FGH = Angle HEF (Transitive property)

Angle FGH = Angle HEF = 90°

Therefore, the statement that will help prove angle FGH is also a right is that angle FGH is the sum of angles FGD and angle DGH which are alternate interior angles to angles HED and DEF which makes up angle HEF, which is a right angle.

b. The two-column method can be used to prove that triangle EHG and triangle GFE are congruent as follows;

Statement. Reason

EF is congruent to HG. Opposite sides of a parallelogram are congruent

EH is congruent FG Opposite sides of a parallelogram are congruent

EG is congruent to EG Reflexive property of congruency

∆EHG is cong. to ∆GFE SSS, Side-Side-Side, congruency rule

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4 0
1 year ago
Simplify the following surd expressions<br> a) 7/3 - 2/3 + V3 - 3V3
Nata [24]

Answer:

\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}    

Step-by-step explanation:

Given the expression

\frac{7}{3}\:-\:\frac{2}{3}\:+\:v^3\:-\:3v^3

solving the expression

\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}

combine the fractions i.e \frac{7}{3}-\frac{2}{3}=\frac{5}{3}

\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}=\frac{5}{3}+\sqrt{3}-3\sqrt{3}

add similar elements  i.e \sqrt{3}-3\sqrt{3}=-2\sqrt{3}

                                 =\frac{5}{3}-2\sqrt{3}      

Thus,

\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}                        

4 0
3 years ago
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