Step-by-step explanation:
2×10,000 + 8×1000 + 5×100+6×10+1
Well just think.. there are 365 days in a year and 55 megawatt hours generated 365 days. so just do 55 divided by 25 since its just a quarter of the year .. hope this helped (:
We can use the subtraction property of logs to expand the right side of the equation:
log(1/H*) = log(1) - log(H*)
No matter what base we’re using, log(1) = 0, so this simplifies to -log(H*). We’re also given a pH value of 3.6, so we can substitute this value into the original equation along with -log(H*) to get
3.6 = -log(H*)
Multiplying by -1 on both sides:
-3.6 = log(H*)
And rewriting in exponential form:
H* = 10^(-3.6) = 0.0003 (rounded to the nearest ten thousandth)
Answer:
Step-by-step explanation:
Find AOS
X = -b/2a
X = -65/2(-14)
X = -65/-28
X = 2.32 secs
t = 2.32secs
A) y value when t = 2.32 is the maximum height.
Substitute t in the equation.
h(t)= -14t^2+65t+1.75
h(t)= (-14 * 2.32²) + (65 * 2.32) + 1.75
= (-14 * 5.38 ) + (65 * 2.32) + 1.75
= -75.35 + 150.8 + 1.75
= 77.2 ft
Maximum height attained by the ball = 77.2 ft
B) Time the maximum height achieved = 2.32secs
C) The ball off of the ground when it was shot is well t = 0
Substitute t in equation
h(t)= -14t^2+65t+1.75
h(0)= (-14 * 0²) + (65 * 0) + 1.75
= 0 + 0 + 1.75ft
The ball is 1.75ft off the ground when it was shot.
