Here first we have to understand which place is 10 thousand.
6- hundred thousand
2- ten thousand
0- thousand
0- hundred
0- ten
0- one
so as we can see 2 is in ten thousands place.
Now rounding ten thousands place is done by looking up to thousands place.
If the digit at thousands place is 5 or greater than 5 then we change our ten thousands value to one digit higher else it remains same.
Here we have 0 at thousands place , which is less than 5 , so we keep the number as it is.
Answer: 620, 000
Answer: 21
Step-by-step explanation:
we have two simple equations:
1) 70=100%
2) x=30%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
70/x=100%/30%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 30% of 70
70/x=100/30
(70/x)*x=(100/30)*x - we multiply both sides of the equation by
70=3.33333333333*x - we divide both sides of the equation by (3.33333333333) to get x
70/3.33333333333=x
The fore, the answer is 21
If a line is parallel to another, the slopes of both lines are the same. So for this problem, you can infer that the slope of the line you're trying to find is 3.
To find the actual equation of the line, you can use the given coordinates and plug them into the point slope form:
y - y1 = m(x - x1)
plug the given y coordinate into y1 and the given x coordinate into x1. m is the slope, so plug in 3 for m.
y - 1 = 3(x +2) Use distributive property for right side of equation
y - 1 = 3x + 6 add 1 to both sides to cancel -1 on left side of equation and isolate y
Equation of line: y = 3x + 7
Fred. .9 is larger than .6 therefore, Fred walked a longer distance.
The two dot plots are missing, so i have attached it.
Answer:
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
From the attached image, we are told to compare the means for each plot to the nearest tenth.
Mean = Σx/n
Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;
(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133
Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles
Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143
Mean of miles run at the end of the school year = 143/14 = 10.2 miles
Thus;
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
