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ivann1987 [24]
3 years ago
9

15 points urgent please help.

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

ima take a wild guess and say a and c is right (im d u m b so i d k)

Step-by-step explanation:

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What is the answer ?
alukav5142 [94]

Answer:

2y

Step-by-step explanation:

Simplifying

21x + -42y = 0

Solving

21x + -42y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '42y' to each side of the equation.

21x + -42y + 42y = 0 + 42y

Combine like terms: -42y + 42y = 0

21x + 0 = 0 + 42y

21x = 0 + 42y

Remove the zero:

21x = 42y

Divide each side by '21'.

x = 2y

Simplifying

x = 2y

8 0
3 years ago
An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers.​ So, 10 adult male passengers can have a m
disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that \mu = 160, \sigma = 35

Sample of 10:

This means that n = 10, s = \frac{35}{\sqrt{10}} = 11.07

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{158 - 160}{11.07}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0
3 years ago
(08.05, 08.06 MC)
babunello [35]

A=16x²-8x+1

16x²-8x+1=l²

(16x²-4x)-(4x+1)=l²

4x(4x-1)-1(4x-1)=l²

x=1/4 or 1

Therefore

since x=1/4

l²=1/4=>l=>√(1/4)

l=1/2

since x=1

l²=1=>l=>√1

l=1

Therefore the length of each sides

1 or 1/2

6 0
3 years ago
I need somebody to hop on my last question i really need help
natita [175]

Ok  ill try but it might be wrong like always

8 0
3 years ago
Read 2 more answers
89 + 217 =<br> 1,564 – 1,438 =<br> 11 X 5 =<br> 72 : 8 =<br> 6 X 10 =<br> 88 + 8 =<br> 4,632-4,608 =
denpristay [2]

Answer:

use a calculator

7 0
3 years ago
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