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Igoryamba
3 years ago
11

1. Find "V". Round to hundreds.V = LWHL= 29.4W = 16.7H = 21.8​

Mathematics
1 answer:
postnew [5]3 years ago
4 0

Volume = 10,700

V = LWH

L = 29.4

W = 16.7

H = 21.8

All we need to do is multiply them all together and then round the answer to get our final answer to the hundreds place.

V = LWH

V = 29.4(16.7)(21.8)

V = 490.98(21.8)

V = 10703.364

Then, we need to round it to the hundreds place.

V = 10,700

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Is Addison has 15 fewer pieces of candy than Ronny does a expression or equation? and why
Anna35 [415]

Let the Addison's candy count be a and Ronny's be r.

Then a = r - 15.  This is an equation.  

If you had a second equation, you could replace a with the expression (r - 15), which in itself is not an equation.

4 0
3 years ago
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The teacher collected some snowfall data during one of the snow days last year. Estimate the total snowfall throughout the day.
Sedaia [141]

The total snowfall throughout the day is the expected value of the distribution.

The estimated total snowfall during the day is 30 inches

Start by calculating the average rate of snow collected on that day.

Rate = \frac{0 + 1.5 + 2.5 + 2.0 +1.0 +0.5}{6}

This gives

Rate = \frac{7.5}{6}

Divide 7.5 by 6

Rate = 1.25

There are 24 hours in a day.

So, the total snowfall is:

Total  = Rate \times Hours

This gives

Total  = 1.25 \times 24

Multiply

Total  = 30

Hence, the estimated total snowfall during the day is 30 inches

Read more about expected values at:

brainly.com/question/13005177

3 0
2 years ago
What is the solution to the system of equations?<br><br> 6x−4y=152<br><br> y=3x−762
Lelu [443]

Answer:

Hi! The correct answer is (1448/3, 686)

Step-by-step explanation:

<u><em>~Solve for the first variable in one of the equations, then substitute the result into the other equation~</em></u>

6 0
2 years ago
Look at the number sentence below. -26 + 75 =
Novosadov [1.4K]
-26+75=43 hope this helps


3 0
4 years ago
Help pls, will mark brainliest
BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be {\sf T_n} is given by ;

  • {\boxed{\bf T_{n}=T_{1}+(n-1)d}}

Where , <u>d</u> is the common difference

Now , here we are given with ;

{\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

{: \implies \quad \sf T_{1}+(5-1)d=T_{5}}

Putting the values and transposing 1st term to RHS , we have ;

{: \implies \quad \sf 4d = -4-8}

{: \implies \quad \sf d=-\dfrac{12}{4}}

{: \implies \quad \sf d=-3}

Now , as we got the common difference , so we can find out the missing terms now ;

{: \implies \quad \sf T_{2}= T_{1}+(2-1)d}

{: \implies \quad \sf T_{2}= 8 +d}

{: \implies \quad \sf T_{2}= 8-3}

{: \implies \quad \bf \therefore \:  T_{2}= 5}

Now

{: \implies \quad \sf T_{3}= T_{1}+(3-1)d}

{: \implies \quad \sf T_{3}= 8 +2d}

{: \implies \quad \sf T_{3}= 8-6}

{: \implies \quad \bf \therefore \:  T_{3}= 2}

Also ,

{: \implies \quad \sf T_{4}= T_{1}+(4-1)d}

{: \implies \quad \sf T_{4}= 8 +3d}

{: \implies \quad \sf T_{4}= 8-9}

{: \implies \quad \bf \therefore \:  T_{4}= -1}

Now , The given table can be written as ;

{\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0
3 years ago
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