4 years ago

How do you find the y-intercept in a quadratic equation

1 answer:

4 0

Find the x-intercept(s). To find the x-intercept let y = 0 and solve for x. You can solve for x by using the square root principle or the quadratic formula (if you simplify the problem into the correct form).

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Which of the following is equivalent to 16/3

Neko [114]

Answer:

Step-by-step explanation:

6÷3=2

9÷3=3

combined that is 15/3

so the extra 1 goes back into the fraction

giving us 5 1/3

6 0

2 years ago

Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A

Artyom0805 [142]

Answer:

(i) U' = Φ

(ii) A∩A' = Φ

(iii) A – ( B U C) = {5,7,9}

(iv) A' U ( B U C ) = {2,4,6,8,10}

(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}

Step-by-step explanation:

8 0

3 years ago

Ms. Zahara had $350.00 in her checking account. She withdrew $25.00 each day on Thursday, Friday, and Saturday. Ms. Zahara got p

Blababa [14]

Answer:

350-es 12

Step-by-step explanation: I think this is right

4 0

2 years ago

Eddie's moving company moved 3 boxes out of Mrs. Diaz's house. The box labeled "kitchen" was 4 times heavier than the box labele

Svetach [21]

K - Kitchen
b - Bedroom
l - Library

k = 4b
l = 14b
k + b + l = 817 pounds
4b + b +14b = 817 pounds
19b = 817 lbs
b = 817/19 pounds
b = 43 pounds

Since k = 4b
k = 4 * 43 pounds
k = 172 pounds

7 0

3 years ago

Adjacent angles have a common vertex and a common side. True or false

Yakvenalex [24]

This is true. Adjacent angles have a common vertex and a common side. 

Adjacent angles are supplementary and are on the same line.

I hope this helps!
~kaikers

7 0

3 years ago