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liubo4ka [24]
3 years ago
9

P divided by 3 as an algebraic expression

Mathematics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

1/3*p

Step-by-step explanation:

Algebraic expressions cannot be quotients, so you must rewrite it as a multiplacation.

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Tiana buys a new cell phone with a retail price of $80.00.
frutty [35]

Answer:

$85.60

Step-by-step explanation:

We add the percentage of sales tax to the total.  This means we are paying 100% + 7% tax, or 107%.

107% = 107/100 = 1.07; this gives us

80(1.07) = 85.60.

7 0
3 years ago
Ruby Company produces a chair for which the standard specifies 5 yards of material per unit. The standard price of one yard of m
azamat

Answer

given,

Standard price = $ 7.50

8,500 chairs were manufactured, using 43,600 yards at a cost of $7.55 per yard.

Price Variance = Actual Quantity x (Actual Rate - Standard Rate)

                         = 43,600 x (7.55 - 7.50)

                         = 2180 (U)

Quantity Variance = Standard Rate x (Actual Quantity - Standard Quantity)

                              = 7.5 x (43600 - 8500 x 5)

                              = 8250 (U)

Cost Variance = 2180+ 8250 = 10430 (U)

3 0
4 years ago
Find the area of quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21)
sasho [114]

Answer:

The area of quadrilateral ABCD is 139 unit^2.

Step-by-step explanation:

Given:

Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).

Now, to find the area.

The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).

So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:

In Δ ABC:

A(x_1,y_1)=(1,1)\:,\:B(x_2,y_2)=(7,-3)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ABC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-3-2)+(7)(2-1)+12(1--3)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(-5)+(7)(1)+12(4)\right|

On solving we get:

Area\,of\,triangle\,=25.

In Δ ADC:

A(x_1,y_1)=(1,1)\:,\:D(x_2,y_2)=(7,21)\:and\:C(x_3,y_3)=(12,2)

Now, to get the area of triangle ADC:

Area\,of\,triangle\,=\,\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|

Area\,of\,triangle\,=\,\frac{1}{2}\left|1(21-2)+(7)(2-1)+12(1-21)\right|

On solving it by same process as above we get:

Area\,of\,triangle\,=114

Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:

25+114\\=25+114\\=139\ unit^2

Therefore, area of quadrilateral ABCD is 139 unit^2.

4 0
3 years ago
Let h(x)=x^2+1<br> h(h(h(3)))<br><br> I got the answer 10202
pashok25 [27]

Answer: 10202

Step-by-step explanation:you are right! I’m pretty sure!

H(3)=10

H(10)=101

H(101)= 10202

6 0
3 years ago
Five to the fifth power minus two to the third power
Anastasy [175]

Answer:

<h3>3117</h3>

Step-by-step explanation:

5^5 - 2^3\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:exponents}\:5^5\::\quad 3125\\\\=3125-2^3\\\\\mathrm{Calculate\:exponents}\:2^3\::\quad 8\\\\=3125-8\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:3125-8\:\\\\:\quad 3117

3 0
3 years ago
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