D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, in ascending order
Q2 (median) = d5 = 2 //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4
Answer:
y=5/3 is the only real solution
Step-by-step explanation:
Solve for y over the real numbers:
11 y^2 - 19 y - 10 = -4 y^2
Add 4 y^2 to both sides:
15 y^2 - 19 y - 10 = 0
The left hand side factors into a product with two terms:
(3 y - 5) (5 y + 2) = 0
Split into two equations:
3 y - 5 = 0 or 5 y + 2 = 0
Add 5 to both sides:
3 y = 5 or 5 y + 2 = 0
Divide both sides by 3:
y = 5/3 or 5 y + 2 = 0
Subtract 2 from both sides:
y = 5/3 or 5 y = -2
Divide both sides by 5:
Answer: |
| y = 5/3 or y = -2/5
Answer:
D. 76
Step-by-step explanation:
because students that has 5 absences and less most likely to get higher than 75 marks. The student who has 8 absences studied at home, he's a genius
The y-intercept is 1/3 or (0, 1/3)
hope this helped !!
