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2 years ago

At a water park, 27 out of 90 tickets sold were child tickets. what percentage of the tickets were child tickets?

Mathematics

1 answer:

Alik [6]2 years ago

3 0

You do 27 divided by 90 27/90=0.3 and then move the decimal two places which would give you 30%

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I need help on #1 #3 #4

mr_godi [17]

1.) Word form: two hundred thirty-six and seventy-seven thousandths

Expanded notation: 200 + 30 + 6 + 0.0 + 0.07 + 0.007

There are no underlines?

3.) tenth: 7.3 hundredth: 7.31 thousandth: 7.305 whole number: 7

4.) Estimate: 10,400

Answer is 10,417

5 0

2 years ago

Read 2 more answers

Which is larger 7/12 or 1/2

White raven [17]

Your answer should be 7/12

7 0

3 years ago

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The following information is obtained from two independent samples selected from two normally distributed populations.

AysviL [449]

A. The point estimate of μ1 − μ2 is calculated using the value of x1 - x2, therefore:

μ1 − μ2 = x1 – x2 = 7.82 – 5.99

μ1 − μ2 = 1.83

B. The formula for confidence interval is given as:

Confidence interval = (x1 –x2) ± z σ

where z is a value taken from the standard distribution tables at 99% confidence interval, z = 2.58

and σ is calculated using the formula:

σ = sqrt [(σ1^2 / n1) + (σ2^2 / n2)]

σ = sqrt [(2.35^2 / 18) + (3.17^2 / 15)]

σ = 0.988297

Going back to the confidence interval:

Confidence interval = 1.83 ± (2.58) (0.988297)

Confidence interval = 1.83 ± 2.55

Confidence interval = -0.72, 4.38

3 0

3 years ago

PLZ HELP BRAIN FAM!!!

RideAnS [48]

It would be 7.45 since the -3.05 and the -9.5 together would equal -12.55 which subtracted from 20 would equal 7.45

5 0

3 years ago

Read 2 more answers

Please help me!

dybincka [34]

Answer:

They are only equal on day 0, both having 10 population.

Step-by-step explanation:

Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

$f(x)=10*2^{\frac{x}{3} }$

Given the bacteria on the stove is measured at 10 and doubles every 4 days we can create another equation:

$f(x)=10*2^{\frac{x}{4} }$

To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

$10*2^{x/3}=10*2^{x/4}$

Divide both sides by 10

$2^{x/3}=2^{x/4}$

Since both exponents have the same base we can set the exponents equal to eachother and solve for x:

$\frac{x}{3}=\frac{x}{4}$

Multiply both sides by 3 to isolate x on the left side

$x=\frac{3x}{4}$

Multiply both sides by 4 to remove fraction

$4x=3x$

Subtract 3x to isolate x on the left side

$x=0$

Plug x into one of our original equations

$f(0)=10*2^{0/3}$

Solve

$f(0)=10$

6 0

1 year ago