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Alex
3 years ago
8

7. Phytochrome prevents seeds of some plants from germinating when they are in deep shade by the: absorption of far-red waveleng

ths by chlorophyll. slow conversion of Pfr to Pr in the dark. absorption of red wavelengths by Pr. absorption of far-red wavelengths by Pfr. slow conversion of Pr to Pfr in the dark.
Biology
1 answer:
SIZIF [17.4K]3 years ago
4 0
<h2>Function of Phytochrome </h2>

Explanation:

  • The <em>color of light</em> that they absorb maximally by the two types such as   <em>Pfr is a blue-green structure</em> that ingests far-<em>red light (730 nm)</em> and<em> Pr is a blue structure that retains red light (660 nm)</em>
  • <em>Pfr assimilates far-red light</em>, it is changed over to the <em>Pr structure</em>
  • Pfr can spontaneously revert to the Pr form  structure in obscurity <em>dark over time = dark reversion Pfr</em> is additionally helpless to proteinases
  • <em>Pfr contains  some red light, so in red light 15% Pr and   there is a parity of 85% Pfr.</em>
  • <em>The  phytochrome (Pr)</em> is changed over to the organically dynamic structure red light with the <em>Pfr under illumination</em>
  • <em>Darkness and Far -red light convert</em> the particle back to the inactive form.
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If a twisted ladder is used as a model of DNA, which parts of a DNA molecule correspond to the sides of the ladder?
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. The rungs of the ladder are formed by complementary pairs of nitrogen bases — A always paired with T and G always paired with C.

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Imagine that y-axis of each graph describes the rate of photosynthesis. Which of the graphs represents the
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Answer:

a. <u>A</u><u> describes the effect of light intensity on photosynthesis.</u>

Explanation:

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It is a rate-limited reaction. Since photons or particles of light provide the energy required for the reaction, high intensities of light increase the photosynthetic rate. From the graph shown, as <u><em>the intensity increases steadily, so does the rate</em></u>- but at too high of an intensity, it ceases to affect the rate of photosynthesis, which becomes constant or plateaus.

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Under physiological conditions, peptide bond formation and degradation both require enzymes, but only formation requires couplin
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Answer:

thermodynamically unstable but kinetically stable.

Explanation:

The complete question is as follows:

Under physiological conditions, peptide bond formation and degradation both require enzymes, but only formation requires coupling to GTP hydrolysis. Based on this information, peptide bonds under physiological conditions are:

A. both thermodynamically and kinetically stable.

B.thermodynamically unstable but kinetically stable.

C.thermodynamically stable but kinetically unstable.

D. both thermodynamically and kinetically unstable.

  • The term thermodynamically unstable refers to the fact that the peptide bonds are prone to breakage under physiological conditions.
  • The reason why one can conclude the thermodynamic instability of the peptide bonds under physiological condition is that there is a need for a source of energy i.e. GTP hydrolysis for the formation of the peptide bond.
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