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Marta_Voda [28]
3 years ago
7

3) INITII equation y=-x+ 4 equation W10 slope (m) = _ y-intercept =

Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer:

slope (m) = 1 and intercept = -4

Step-by-step explanation:

comparing with Y = mX - c

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Is - 29/8 < , > or = - 3.62
andreyandreev [35.5K]
When -29/8 is written as a decimal it becomes
- 3.625
Which is equivalent to -3.63, rounded to the nearest hundredth.

Now from here we will be able to tell if they're < , > or =

So, -3.63 is > -3.62

ANSWER: -29/8 > -3.62
3 0
3 years ago
Find the x-intercept and y-intercept<br> from the following linear equation:<br> -2x + 4y = -16
irina1246 [14]

Answer:

x-intercept: (8, 0)

y-intercept: (0, -4)

Step-by-step explanation:

7 0
3 years ago
What is the answer please help
maria [59]

Answer:

25

Step-by-step explanation:

x^2=24^2+7^2

    =576+49

   =625

x=25

8 0
4 years ago
Enter the value of p so the expression 5/6 - 1/3n equivalent to p(5-2n)
lawyer [7]
\frac{5}{6}- \frac{1}{3} n
p(5-2n)=5p-2np
5p=\frac{5}{6}
p=\frac{1}{6}

-2np=-2n\frac{1}{6}=\frac{-2n}{6}=-\frac{1}{3}n
3 0
3 years ago
). If a, ß are zeroes of the quadratic polynomial p(x)=kx²+4x+4 such
natta225 [31]

Answer:

The values of k are 2/3 and -1

Step-by-step explanation:

Product of zeros = αβ= constant  / coefficient of x^2 =  4/k

Sum of zeros =α+β = - coefficient of x / coefficient of x^2= -4/k

Given

Consider a= α and b= β

(\alpha)^2 + (\beta)^2 = 24

(\alpha)^2 + (\beta)^2 can be written as (\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 if we add \pm 2 (\alpha)(\beta) in the above equation.

(\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 -2(\alpha)(\beta)

(\alpha + \beta)^2 -2(\alpha)(\beta)

Putting values of αβ and α+β

(\frac {-4}{k})^2 -2( \frac {4}{k}) = 24\\\frac {16}{k^2} - \frac {8}{k} = 24\\Multiplying\,\, the \,\, equation\,\, with\,\, 8K^2\\ 2 - k= 3K^2\\3k^2-2+k=0\\or\\3k^2+k-2=0\\3k^2+3k-2k-2=0\\3k(k+1)-2(k+1)=0\\(3k-2)(k+1)=0\\3k-2=0 \,\,and\,\, k+1 =0\\k= 2/3 \,\,and\,\, k=-1

The values of k are 2/3 and -1

8 0
4 years ago
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