All categories

4 years ago

Which ordered pair is a solution to the system of equations?

1 answer:

7 0

The third one is the correct answer
instead of going through the long process of the simultaneous equation just input the first number for the x into the equation and 2nd for y and you get your answer

You might be interested in

Square of a standard normal: Warmup 1.0 point possible (graded, results hidden) What is the mean ????[????2] and variance ??????

LenaWriter [7]

Answer:

$E[X^2]= \frac{2!}{2^1 1!}= 1$

$Var(X^2)= 3-(1)^2 =2$

Step-by-step explanation:

For this case we can use the moment generating function for the normal model given by:

$\phi(t) = E[e^{tX}]$

And this function is very useful when the distribution analyzed have exponentials and we can write the generating moment function can be write like this:

$\phi(t) = C \int_{R} e^{tx} e^{-\frac{x^2}{2}} dx = C \int_R e^{-\frac{x^2}{2} +tx} dx = e^{\frac{t^2}{2}} C \int_R e^{-\frac{(x-t)^2}{2}}dx$

And we have that the moment generating function can be write like this:

$\phi(t) = e^{\frac{t^2}{2}$

And we can write this as an infinite series like this:

$\phi(t)= 1 +(\frac{t^2}{2})+\frac{1}{2} (\frac{t^2}{2})^2 +....+\frac{1}{k!}(\frac{t^2}{2})^k+ ...$

And since this series converges absolutely for all the possible values of tX as converges the series e^2, we can use this to write this expression:

$E[e^{tX}]= E[1+ tX +\frac{1}{2} (tX)^2 +....+\frac{1}{n!}(tX)^n +....]$

$E[e^{tX}]= 1+ E[X]t +\frac{1}{2}E[X^2]t^2 +....+\frac{1}{n1}E[X^n] t^n+...$

and we can use the property that the convergent power series can be equal only if they are equal term by term and then we have:

$\frac{1}{(2k)!} E[X^{2k}] t^{2k}=\frac{1}{k!} (\frac{t^2}{2})^k =\frac{1}{2^k k!} t^{2k}$

And then we have this:

$E[X^{2k}]=\frac{(2k)!}{2^k k!}, k=0,1,2,...$

And then we can find the $E[X^2]$

$E[X^2]= \frac{2!}{2^1 1!}= 1$

And we can find the variance like this :

$Var(X^2) = E[X^4]-[E(X^2)]^2$

And first we find:

$E[X^4]= \frac{4!}{2^2 2!}= 3$

And then the variance is given by:

$Var(X^2)= 3-(1)^2 =2$

7 0

3 years ago

A group of 10 people were shown 15 photographs. Each person was asked to choose their favourite photo, and the choices were reco

devlian [24]

The data type of the recorded data is a. nominal.

In statistics, there are different types of data which includes nominal, ordinal, ratio, and interval data.

For nominal data, they are mainly used for identification and classification of variables. or simply put, they are used for labelling variables and has no numerical value attached to them.

In the example given above, each recorded choice of each person in the group would be recorded as nominal data for the sake of classification. The photographs can be labelled using letters or assigned numbers. However, these numbers are merely for identification purpose.

Therefore, the data type recorded is a. nominal.

Learn more about data type here:

brainly.com/question/14189587

6 0

3 years ago

Antonio uses this redipe to make a fruit smoothie. Fruit Sinoothie eup orange juice cup Yogurt Nino no Cup Strawberries eup blue

ozzi

Answer:

I think it's B.

Step-by-step explanation:

Hope this helps. :)

7 0

2 years ago

Percent decrease from 145 to 132. Round to the nearest percent

o-na [289]

132/145 × 100% = 91.03%

i am a mathematics teacher. if anything to ask please pm me

5 0

3 years ago

In a particular game of chance, a wheel consists of 42 slots numbered 00, 0, 1, 2,...,40. To play the game, a metal ball is

Nikolay [14]

Answer:

The sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

Step-by-step explanation:

Consider the provided information.

In probability theory, the set of all possible outcomes or outcomes of that experiment is the sample space of an experiment or random trial. Using set notation, a sample space is usually denoted and the possible ordered outcomes are identified as elements in the set.

Here the possible number of elements in the set are 00, 0, 1, 2,...,40

The sample space is anything the ball can land on.

Thus, the sample space for one spin of this game is: S = {00, 0, 1, 2, 3,…, 40}

6 0

3 years ago