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3 years ago

What is one square base and four triangular lateral faces?

Mathematics

2 answers:

cricket20 [7]3 years ago

8 0

Answer:

a square pyramid

Step-by-step explanation:

its easy ;)

Alchen [17]3 years ago

5 0

Answer:

A sqaure pyramind

Step-by-step explanation:

I googled it Lol.

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Ellie want to buy new shoes that is in sale for $80. She saved $60. How much more money does she need

mel-nik [20]

Answer:

$20

Step-by-step explanation:

New shoes = $80

What Ellie Saved = $60

80 - 60 = 20

To make sure this is correct simply add 20 to 60.

60 + 20 = 80

4 0

3 years ago

Read 2 more answers

Someone please help me I’m literally struggling

Darya [45]

Hello,

We have :

27 = 3³ = 3 × 3 × 3

$x$ ³ = $x$ × $x$ × $x$

So :

The cube root of 27 $x$ ³ is :

3 × $x$ = 3 $x$

( because : (3 $x$ )³ = 27 $x$ ³ )

We have :

8 = 2³ = 2 × 2 × 2

So :

The cube root of 8 is : 2

$a^{3} +b^{3} = (a+b)(a^{2} -ab+b^{2} )$ with $a=3x$ and $b=2$

We have :

$(3x)^{3}+2^{3}=(3x+2)((3x)^{2} -(3x)(2)+(2 )^{2} )$

Have a nice day :)

6 0

3 years ago

Read 2 more answers

Please find this answer

Semenov [28]

Answer: I cant see the picture so I cant help sorry

Step-by-step explanation:

3 0

3 years ago

What is 10 4/5 minus 3 1/2

Oksanka [162]

The answer is 7.3 or in other words 7 3/10

Hope I helped

4 0

4 years ago

Read 2 more answers

Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul

anyanavicka [17]

Answer:

5536 calculators

Step-by-step explanation:

We integrate the function dx/dt to obtain the number of new calculators between beginning of the 3rd week and end of week 4. Note that beginning of 3rd week is the same as end of 2nd week. So, $\int\limits^4_2 {\frac{dx}{dt} } \, dx$ = $\int\limits^4_2 {5000 (1 - \frac{100}{(t +12)^{2} }) } \, dx$

Let u = t + 12, then $\frac{du}{dt}$ = 1. So, du = dt. We also change the limits of our integration. So, when t = 2, u = 2 + 12 = 14 and when t = 4, u = 4 + 12 = 16

Then $\int\limits^4_2 {5000(1 -\frac{100}{(t+12)^{2} } )} \, dx$ = ∫₁₄¹⁶ ${5000(1 -\frac{100}{u^{2} } )} \, du = 5000[ u + \frac{100}{u} ]$ ₁₄¹⁶ = $5000[16 + \frac{100}{16} - (14 + \frac{100}{14} )] = 5000 [16 - 14 + \frac{100}{16} - \frac{100}{14} ] = 5000 [2 + \frac{100}{16} - \frac{100}{14} ] = 5535.7$

≈ 5536 calculators

3 0

4 years ago